Answer:
none of the above
Step-by-step explanation:
The perpendicular line will have a slope that is the negative reciprocal of the given slope, so it is ...
m = -1/(-3/2) = 2/3
The point-slope form of the equation of the line with slope m through point (h, k) can be written ...
y = m(x -h) +k
For this slope and the point (6, 3), the equation of the line is ...
y = (2/3)(x -6) +3
y = 2/3x -4 +3
y = 2/3x -1 . . . . . matches none of the offered choices
_____
The attached graph shows this equation is the one that goes through the given point.
Density=mass/volume or d=m/v and the volume of a cube is s^3
We are given that s=2 and m=10 so
d=10/(2^3) g/cm^3
d=10/8 g/cm^3
d=1.25 g/cm^3
Answer:
What is your question?
Step-by-step explanation:
I don't get what your asking
keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above
![x + y =3\implies y=-x+3\implies y=\stackrel{\stackrel{m}{\downarrow }}{-1}x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D3%5Cimplies%20y%3D-x%2B3%5Cimplies%20y%3D%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B-1%7Dx%2B3%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Answer:
its 3/5 so you just add the numerator to the numerator and add the denominator to the denominator.