What is the equation of a line that passes through the point (6,3) and is perpendicular to a line with a slope of -3/2
1 answer:
Answer:
none of the above
Step-by-step explanation:
The perpendicular line will have a slope that is the negative reciprocal of the given slope, so it is ...
m = -1/(-3/2) = 2/3
The point-slope form of the equation of the line with slope m through point (h, k) can be written ...
y = m(x -h) +k
For this slope and the point (6, 3), the equation of the line is ...
y = (2/3)(x -6) +3
y = 2/3x -4 +3
y = 2/3x -1 . . . . . matches none of the offered choices
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The attached graph shows this equation is the one that goes through the given point.
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