Answer:
Zeros of the given function are x=5 and x=-1.
Step-by-step explanation:
f(x)=x^2-4x-5
f(x)=x^2+1x-5x-5
f(x)=x(x+1)-5(x+1)
f(x)=(x-5)(x+1)
To find zeros, we need to set f(x)=0
0=(x-5)(x+1)
0=(x-5) or 0=(x+1)
0=x-5 or 0=x+1
5=x or -1=x
Hence zeros of the given function are x=5 and x=-1.
We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.
That will give the final graph as attached below:
for x=0,
f(x)=x^2-4x-5
f(0)=0^2-4(0)-5
f(0)=0-0-5
f(0)=-5
Hence first point is (0,-5)
Similarly we can find more points.
according to cosine
cosine= <u> </u><u> </u><u>Adj</u><u> </u><u> </u><u> </u><u> </u>
opp
C=28/195
Step-by-step explanation:
the functional graph is the line.
a functional graph is always showing the direct relationship between a value on one coordinate axis with a value in the other coordinate axis
here it is between the price in dollars (as we can understand it : per unit) and the number of units sold.
clearly, the more units we sell, the cheaper we have to make the price per unit.
the question is how many units can be sold for a given price ($60).
so, I find the given price on the price axis (in this case the vertical axis), go then along that price all the way to the right until I hit the function line, and then go straight down to the unit axis and see what value I am hitting there : 80. which means 80,000 units.
so, I can sell 80,000 units for $60 per unit.
Answer:
I'm stuck on that question too
Step-by-step explanation:
