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laila [671]
3 years ago
6

Use the degree and end behavior to match each polynomial to its graph.

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:need brainless upuls Ashe sorry

Step-by-step explanation:sorry

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See question in image and show workings​<br><br>Note : 1 nautical mile = 1.86km
ycow [4]

Answer:

a)

AB is on the latitude 30°N.

<u>Find AB:</u>

  • AB = 2*3.142*6400*cos 30°*(32+35)/360 = 6482.15 km

BC is along longitude 35°W

<u>Find BC:</u>

  • BC = 2*3.142*6400*(30 + 20)/360 = 5585.77 km

<u>Total distance traveled:</u>

  • 6482.15 + 5585.77 = 12067.92 km

<u>Convert the distance to nautical miles:</u>

12067.92/1.86 = 6488.13 nautical miles

b)

<u>Find the average speed:</u>

  • 6488.13/22 = 294.92 nautical miles / hour

<u>Note</u>. <em>This is unrealistically high speed for a ship, this must be a plane or the time given wrong.</em>

3 0
2 years ago
Solve 12 3/8 divided by 5 1/2 <br><br><br> Please explain :)
ella [17]

Answer:9/4

Step-by-step explanation:

99/8*2/11=9/4*1/1=9/4

You can cancel out 99 and 11 to 9 and 1 as they are multiples of eac hother and you can do the same for 8 and 2 to 4 and 1

7 0
3 years ago
Read 2 more answers
A rectangular school yard 280 meters by 245 meters is to be fenced. How many meters of fencing will be required to fence it comp
NemiM [27]
525 or 68,600. It's one of them.
6 0
4 years ago
Read 2 more answers
The sum of four consecutive odd numbers is 40 what is the greatest of the four numbers
TEA [102]

Answer:

13

Step-by-step explanation:

First find the average the numbers (40 / 4 = 10)

2 are more and 2 are less

7, 9, 11, 13

7 0
3 years ago
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What value of c makes the equation true? c – 23.7 = 8.5 31.2 15.2 14.2 32.2
fomenos

Answer:

32.2 is your answer for c

Step-by-step explanation:

Note the equation:

c - 23.7 = 8.5

Note the equal sign. What you do to one side, you do to the other. Isolate the c. add 23.7 to both sides

c - 23.7 (+23.7) = 8.5 (+23.7)

c = 8.5 + 23.7

Simplify.

c = 32.2

32.2 is your answer for c

~

5 0
3 years ago
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