Answer:
Step-by-step explanation:
THIS PIC IS VERY GOOD BUT NOT CLEAR SO I HELP YOU
15,17,19
Suppose the three odd integers are #n#, #n+2# and #n+4#
Their sum is:
#n + (n+2) + (n+4) = 3n+6#
#13# more than twice the largest of the three is:
#2(n+4)+13 = 2n+21#
From what we are told these two are equal:
#3n+6 = 2n+21#
Subtract #2n+6# from both sides to get:
#n = 15#
So the three integers are:
#15, 17, 19#
Step-by-step explanation:
First solve for y
given equation is 3x-2y ≥ 12
subtract 3x on both sides of the equation which would result with: -2y ≥ 12-3x
divide by -2 on both sides of the equation, flip the sign to ≤ because you are dividing by a negative, then you should get the result y<u> </u><u>≤</u><u> </u>-6 + 3x/2 (should look like a fraction)
y-intercept is at -6
slope is 3/2 (or three halves)
start at -6 on the y-axis, go up 3 across 2 and plot your point, keep repeating when going up and down the graph
Answer:D 16inches by 8 inches
Step-by-step explanation:
(2x + 3)⁵
(2x + 3)(2x + 3)(2x + 3)(2x + 3)(2x + 3)(2x + 3)
(2x(2x + 3) + 3(2x + 3))(2x(2x + 3) + 3(2x + 3)(2x + 3)
(2x(2x) + 2x(3) + 3(2x) + 3(3))(2x(2x) + 2x(3) + 3(2x) + 3(3))(2x + 3)
(4x² + 6x + 6x + 9)(4x² + 6x + 6x + 9)(2x + 3)
(4x² + 12x + 9)(4x² + 12x + 9)(2x + 3)
(4x²(4x² + 12x + 9) + 12x(4x² + 12x + 9) + 9(4x² + 12x + 9))(2x + 3)
(4x²(4x²) + 4x²(12x) + 4x²(9) + 12x(4x²) + 12x(12x) + 12x(9) + 9(4x²) + 9(12x) + 9(9))(2x + 3)
(16x⁴ + 48x³ + 36x² + 48x³ + 144x² + 108x + 36x² + 108x + 81)(2x + 3)
(16x⁴ + 48x³ + 48x³ + 36x² + 144x² + 36x² + 108x + 108x + 81)(2x + 3)
(16x⁴ + 96x³ + 216x² + 216x + 81)(2x + 3)
16x⁴(2x + 3) + 96x³(2x + 3) + 216x²(2x + 3) + 216x(2x + 3) + 81(2x + 3)
16x⁴(2x) + 16x⁴(3) + 96x³(2x) + 96x³(3) + 216x²(2x) + 216x²(3) + 216x(2x) + 216x(3) + 81(2x) + 81(3)
32x⁵ + 48x⁴ + 184x⁴ + 288x³ + 432x³ + 648x² + 432x² + 648x + 162x + 243
32x⁵ + 232x⁴ + 720x³ + 1080x² + 810x + 243
