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emmainna [20.7K]
3 years ago
11

What are the vertical and horizontal asymptotes for the function f(x)=(3x^2/x^2-4)

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0
The vertical asymptotes are calculated by solving the equation dominator=0
x^2-4=0
(x-2)(x+2)=0
x=2 and x=-2 are vertical 

The horizontal asymptote is calculated by dividing the leading terms.
3x^2/x^2 = 3
y=3 is <span>horizontal asymptote</span>
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Answer: 8 hours.

Step-by-step explanation:

We have the relation:

Time  = distance/velocity

Distance = 50 miles

Velocity in horse = 9mph

Velocity walking = 3 1/2 mph = 3.5 mph

Then, if T is the total time, X is the distance that he travels in horse and Y is the distance that he travels by foot, we have:

X + Y = 50 miles:

T/2 = X/9mph

T/2 = Y/3.5mph

Then we have:

X/9mph = Y/3.5mph

X = Y*(9/3.5)

And by the first relation:

X = 50 mi - Y

then we have:

50mi - Y = Y*(9/3.5)

50mi = Y + Y*(9/3.5) = Y*(1 + 9/3.5) = Y*3.57

Y = 50mi/3.57 = 14mi

Then we have:

T/2 = 14mi/3.5mph

T = 2*(14/3.5) hours = 8 hours

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3 years ago
Whats the GCF for 9x+36
8_murik_8 [283]

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3 years ago
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If a triangle is reflected across the y-axis, what are the coordinates of the image of point F? Use FGH to answer the question.
alex41 [277]
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Answer:

a = 6.7m is the answer.

Step-by-step explanation:

a = ?

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