All categories

3 years ago

What are the vertical and horizontal asymptotes for the function f(x)=(3x^2/x^2-4)

1 answer:

8 0

The vertical asymptotes are calculated by solving the equation dominator=0
x^2-4=0
(x-2)(x+2)=0
x=2 and x=-2 are vertical

The horizontal asymptote is calculated by dividing the leading terms.
3x^2/x^2 = 3
y=3 is horizontal asymptote

You might be interested in

What is the equation of the line?

svetlana [45]

Answer:

y = -7

Step-by-step explanation:

This line is a horizontal line [HOY] - horizontal, 0 slope, and the equation starts with y = ___ , since it crosses at -7, then the line is y = -7

3 0

3 years ago

Is 60n + 12 equal to 12(5n + 1)

hram777 [196]

Answer: no

Step-by-step explanation:

5 0

3 years ago

Angelica’s bouquet of a dozen roses contains 5 white roses. The rest of the roses are pink. What fraction of the bouquet is pink

PolarNik [594]

7/12 for pink roses (:

7 0

3 years ago

Read 2 more answers

A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a

zavuch27 [327]

Answer:

$Area = 3\dfrac{15}{16}\ sq\ ft$

Area is greater than $3\frac{1}{2}$ sq ft.

Step-by-step explanation:

Length of rectangular sign board = $3\frac{1}{2}$ ft

Width of rectangular sign board = $1\frac{1}{8}$ ft

Area of a rectangle is given by the formula:

$A = Length \times Width$

To find the area, we are going to multiply $3\frac{1}{2}$ with $1\frac{1}{8}$ .

$1\frac{1}{8}$ is greater than 1.

Therefore the multiplication will be greater than $3\frac{1}{2}$ .

Hence, we can say that area will be greater than $3\frac{1}{2}$ sq ft.

Area of the sign:

$A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft$

8 0

3 years ago

What is the answer? I’m new here so please answer it?

11Alexandr11 [23.1K]

Answer:

$258 I think

Step-by-step Explanation:

3 0

3 years ago