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2 years ago

Identify the relationship (complementary, linear pair/supplementary, or vertical) and find the value of x in the image below.

Mathematics

1 answer:

Bezzdna [24]2 years ago

8 0

Answer:

Complementary and x = 24°

Step-by-step explanation:

→ Recognise that angles on a straight line add up to 180°

x + 8° + 148° = 180°

→ Simplify equation

x + 156° = 180°

→ Minus 156° from both sides of the equation to isolate x

x = 24°

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The probability that Brock scores a penalty kick is LaTeX: \frac{3}{10}3 10 . If he shoots 50 penalty kicks, how many "goals" ca

Feliz [49]

Answer:

15 goals out of 50 penalty kicks was scored by brock

Step-by-step explanation:

If Brock shoots 50 penalty kicks and the probability that he scores a penalty kick is 3/10, the number of goal brock is expected to make can be expressed as:

Number of goals scored = probability value * total penalty kicks taken

Number of goals scored = $\frac{3}{10}*50$

Number of goals scored = $15 goals$

5 0

2 years ago

5.22 write the decimal as a fraction or mixed number in simplest form

Vikentia [17]

Answer:

5 and 11/50

Step-by-step explanation:

5.22 = 261/50 = 5 and 11/50

5 0

2 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

2 years ago

In the given diagram, which of the following can you use to prove that triangle ABC is an isosceles triangle?

docker41 [41]

The answer is D) I just went over this.

6 0

3 years ago

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Find the values of the six trigonometric functions for angle G.<br>

VLD [36.1K]

Answer:

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