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mr_godi [17]
3 years ago
7

PLEASE PLEASE HELP IM BEGGING

Mathematics
1 answer:
lesantik [10]3 years ago
6 0
Density = mass / volume.

Book density = 2000 grams / cm^3

Apple volume = 125 mL

Football mass = 400g

Gold density = 20 grams / cm^3

Soup volume = 200 cm^3

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The measure of angle BFE is 120°. Find M angle EFD.
Varvara68 [4.7K]
120 + 120 + X + X = 360
240 + 2X = 360
2X = 120
X = 60
6 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Plsss help (Cuz i'm dumb:D) Calculate the surface area of the prism below, shape below
marin [14]
Surface area of the the rectangles:
8 * 5 + 8 * 4 + 8 * 3 = 96

Surface area of the two triangles:
Use bh/2 base time height over 2
(4 * 3)/2 = 6
There are 2 triangles, 2 * 6 = 12

12 + 96 = 108
5 0
3 years ago
Determine whether the recursive sequence defined by an =1 , an+1 = 5+an diverges or converges. Find the limit if it converges.
zepelin [54]

Answer:

4 equals 1 is the answer

Step-by-step explanation:

8 0
3 years ago
What is the equation of a line passing through the point (-3,5) and has a slope of -6
IceJOKER [234]

Answer:

y = -6x — 13

Step-by-step explanation:

use y = mx + b equation and plug in what you know.

5 = -6(-3) + b —> solve for b

b = -13 —> plug in what you know into y=mx+b

ANSWER: y = -6x — 13

3 0
3 years ago
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