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Daniel [21]
3 years ago
5

If (-2,4) are the coordinates of a point on the line whose equation is y=Mx+1 , what is the slope of the line?

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Slope of the line is -3/2

Step-by-step explanation:

  • Step 1: Given that (-2, 4) is a point on the line y = mx + 1, find slope m.

Since the point is on the line, the coordinates will satisfy the equation.

⇒ 4 = m × -2 + 1

⇒ 4 = -2m + 1

⇒ 3 = -2m

∴ m = -3/2

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General Idea:

If we have a quadratic function of the form f(x)=ax^{2} +bx+c , then the function will attain its maximum value only if a < 0 & its maximum value will be at x=-\frac{b}{2a} .

Applying the concept:

The height h is modeled by h = −16t^2 + vt + c, where v is the initial velocity, and c is the beginning height of the firecracker above the ground. The firecracker is placed on the roof of a building of height 15 feet and is fired at an initial velocity of 100 feet per second. Substituting 15 for c and 100 for v, we get the function as h=-16t^2+100t+15.

Comparing the function f(x)=ax^{2} +bx+c with the given function h=-16t^{2} +100t+15, we get a = -16, b = 100 and c=15.

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The maximum height is found by substituting t=3.125 in the function as below:

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Conclusion:

<u>Yes !</u> The firecracker reaches a height of 100 feet before it bursts.

6 0
3 years ago
so yes i'm re-posting this same question since last time no one answered it for me so this time somebody please help me out :(​
alexandr402 [8]

Answer:

its 30

Step-by-step explanation:

if you see the x is in the middle of the line meaning its 30

5 0
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