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Tema [17]
3 years ago
13

In a genetics experiment on peas, one sample of offspring contained green peas and yellow peas. Based on those results, estimate

the probability of getting an offspring pea that is green. Is the result reasonably close to the value of that was expected? 350 127 3 4 The probability of getting a green pea is approximately . (Type an integer or decimal rounded to three decimal places as needed.) Is this probability reasonably close to ? Choose the correct answer below. 3 4 A. No, it is not reasonably close. B. Yes, it is reasonably close.
Mathematics
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

The probability of getting an offspring pea that is green is is 0.733

YES, the probability is reasonably close to the expected value of 3/4 (0.750)

Step-by-step explanation:

The formula for calculating the probability of an event is;

P = Favorable Outcome / Sample space

Let A be an event of getting an offspring green peas, B be an event of getting an offspring yellow peas and N be the total number of peas.

number of green peas in an offspring are 350

number of yellow peas in an offspring are 127

total number of peas are 477    

So in the genetic experiment, the number of times event A occurs is 350 and the number times event B occurs is 127

Now the probability of getting an offspring pea that is green is

P = number of green peas / total number of peas

p = n(A)/N

p = 350/477

p = 0.733

So YES, the probability is reasonably close to 3/4 ( 0.750 )

The probability of getting an offspring pea that is green is is 0.733.

YES, the probability is reasonably close to the expected value of 3/4 (0.750)

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Answer:

1. 44.8

2. 9.6

3. 61.11

4. 50.41

5. 169

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13. 1.44

14. id k

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d. 31.5

Step-by-step explanation:

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7 0
2 years ago
If two trucks leave a given city on highways making an angle of 132 degrees with one another, traveling at 45 and 55 miles per h
Law Incorporation [45]

Answer:

183 miles to the nearest mile.

Step-by-step explanation:

Distance =Speed X Time

Distance of Truck B from point A=45 X2 =90 miles

Distance of Truck C from point A=55 X2 =110 miles

Angles between them, BAC=132°

We want to find the Distance BC denoted by a between the trucks.

Using Cosine Rule,

a²=b²+c²-2bcCos A

=90²+110²-(2X90X110XCos132°)

=33448.79

a=√33448.79

BC=182.89 miles

The distance between the trucks is 183 miles to the nearest mile.

3 0
3 years ago
Read 2 more answers
Which one should I choose
Mila [183]
The best choice would be neither
3 0
3 years ago
I really need answers asap please.
ale4655 [162]

We're told x=-5 and y=11 and asked to evaluate a few expressions. That just means substitute these values into the expressions and compute the exact numerical answer.

4y-10x = 4(11) - 10(-5) = 44 + 50 = 94

Answer: 94

x to the power of 3

x^3 = (-5)^3 = -5 \times -5 \times -5 = -125

Answer: -125

•6y to the power of 2

Probably means

6y^2 = 6(11)^2 = 6(121) = 726

Answer: 726

5(3x+2y) = 5(3(-5) + 2(11)) = 5(-15 + 22) = 5(7) = 35

Answer: 35

•(y-x) to the power of 2

(y - x)^2 = (11 - -5)^2 = 16^2 = 256

Answer: 256


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