3 years ago

Use the distance formula to decide whether ab=bc A(4,2) B(-1,-1) C(-6,-4)

1 answer:

4 0

$AB= \sqrt{(-1-4)^2+(-1-2) ^{2} }= \sqrt{(-5)^2+(-3)^2}= \sqrt{34} \\ \\ BC= \sqrt{(-6+1)^2+(-4+1) ^{2} }= \sqrt{(-5)^2+(-3)^2}= \sqrt{34} \\ \\ \sqrt{34}= \sqrt{34} \ \ \to \ \ AB=BC$

You might be interested in

Im so lost im in algebra 1 and i feel so slow

Andrei [34K]

Answer:

Hey but you get better at in no time lol

Step-by-step explanation:

no need to worry

7 0

2 years ago

Enter your answer, in simplest radical form.

Alexus [3.1K]

Answer: 30x $\sqrt{2y}$

Step-by-step explanation:

$\sqrt{6x}$ x $\sqrt{15xy}$ x $\sqrt{20}$

This can also be written as :

$\sqrt{6x.15xy.20}$

= $\sqrt{1800x^{2}y}$

which could be written as :

$\sqrt{900x^{2}}$ x $\sqrt{2y}$

= 30x $\sqrt{2y}$

4 0

3 years ago

Which of the following statements is not true?

Lady bird [3.3K]

Statement: Your question is well elaborate and has all needed data.

6 0

3 years ago

Read 2 more answers

There are 205 coins in a jar all of which are either nickles or quarters . The vaule of the coin in the jar is $31.85. if both o

Gnesinka [82]

Answer: There are 97 nickels and 108 quarters.

Step-by-step explanation:

Let x = Number of nickels, y = Number of quarters.

As per given,

x+y = 205 ...(i)

0.05x+0.25y = 31.85 ... (ii) [1 nickel = $0.05, 1 quarter = $ 0.25]

Multiply (ii) by 20, we get

x+5y=637 ...(iii)

Eliminate (i) from (iii)

4y = 432

⇒ y = 108 [Divide both sides by 4]

Put value of y in (i), we get

$108+x=205\Rightarrow\ x= 97$

Hence, there are 97 nickels and 108 quarters.

6 0

3 years ago

HELPP is c Right?? picture shown

Crank

Hello :
the midepoint is( (-1+7)/2 ; (3+2)/2)
(3, 5/2) ... answer C

8 0

3 years ago