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4 years ago

Use the distance formula to decide whether ab=bc A(4,2) B(-1,-1) C(-6,-4)

1 answer:

4 0

$AB= \sqrt{(-1-4)^2+(-1-2) ^{2} }= \sqrt{(-5)^2+(-3)^2}= \sqrt{34} \\ \\ BC= \sqrt{(-6+1)^2+(-4+1) ^{2} }= \sqrt{(-5)^2+(-3)^2}= \sqrt{34} \\ \\ \sqrt{34}= \sqrt{34} \ \ \to \ \ AB=BC$

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What is the solution to the equation? Sqrt. 2x+10-6=2 <br><br><br> Please show all steps

hichkok12 [17]

Answer: x = 27

Solution, showing all steps:

1) equation:   $\sqrt{2x+10}-6=2$

2) Clear the square root:

=>    $\sqrt{2x+10} =2+6$

=>    $\sqrt{2x+10} =8$

3) Square both sides of the equality:

=> $2x + 10 = 8^2=64$

4) Clear x:

2x = 64 - 10

2x = 54

x = 54 / 2

x = 27.

5) Verify that this is not a straneous solutio, by replacing the solution in the equation:

$\sqrt{2(27)+10} -6= 2

 \sqrt{54+10}-6=2

 \sqrt{64} -6=2

8-6=2

2=2$

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3 years ago

Find the perimeter P of

nataly862011 [7]

Answer:

P = 3.6 + 6 + 3.6 + 6 = 19.2 units

Step-by-step explanation:

distance between (-3,-2) and (-5,-5) =

Sqrt[(-5-3)^2+(-5 - -2)^2]

Sqrt (4+9) = 3.6

d = (-5,-5) and (1,-5) =

Sqrt[(1 - - 5)^2 + (-5 - - 5)^2]

= sqrt (36 + 0) = 6

d = (1,5) and (3,-2)

Sqrt[(1 - - 3)^2 + (-5 - - 2)^2]

Sqrt(4+9) = 3.6

d = (3,-2) and (-3,-2)

Sqrt[(-3-3)^2 + (-2 - - 2)^2]

Sqrt (36+0) = 6

4 0

3 years ago

What is the answer to 13u − 11u = 10

Anarel [89]

Answer:

Step-by-step explanation:

$13u-11u=0\qquad\text{combine like terms}\\\\(13-11)u=0\\\\2u=0\qquad\text{divide both sides by 2}\\\\\dfrac{2u}{2}=\dfrac{0}{2}\\\\u=0$

6 0

4 years ago

Read 2 more answers

Find the Secant <H<br><br>see photo for answer instructions

exis [7]

Answer:

for angle H ,

hypotenuse = gh( √77)

adjacent side= ih( √35)

perpendicular=gi( √42)

then

we know

secant=hypotenuse /adjacent

=√77/√35

5 0

3 years ago

There is a box of pencils on Ms. Romero's desk Seven pencils, laid side

Veronika [31]

2 because I am correct

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3 years ago