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3 years ago

Can you answer those questions

Mathematics

1 answer:

alexandr402 [8]3 years ago

7 0

Step-by-step explanation:

the image u have shared is too much covered by focus light send it again

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How to do composition of functions

KengaRu [80]

<h2><u><em>If you rather have the link to get this info lmk!!</em></u></h2>

Example: f(x) = 2x+3 and g(x) = x2

"x" is just a placeholder. To avoid confusion let's just call it "input":

f(input) = 2(input)+3

g(input) = (input)2

Let's start:

(g º f)(x) = g(f(x))

First we apply f, then apply g to that result:

Function Composition - (g º f)(x) = (2x+3)2

What if we reverse the order of f and g?

(f º g)(x) = f(g(x))

First we apply g, then apply f to that result:

Function Composition - (f º g)(x) = 2x2+3

We get a different result! When we reverse the order the result is rarely the same. So be careful which function comes first.

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5 0

3 years ago

Look at pic below... please do it.. need correct answer.. i will mrk brsinliest hurry.. need help..

galina1969 [7]

The answer to this question is B

5 0

3 years ago

Read 2 more answers

Find a cubic polynomial in standard form with real coefficients, having the zeros 4 and 5i. Let the leading coefficient be 1.

SCORPION-xisa [38]

If one of our zeros is 4, then the factor is x-4. If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i. So our 3 factors are (x-4)(x+5i)(x-5i). We will FOIL out these factors to get the polynomial. Let's start with the ones that contain the imaginary numbers. Doing that mutliplication we get x^2-25i^2. i^2 is equal to -1, so what that expression simplifies down to is $x^{2} +25$ . Now we will multiply in that last factor of (x-4): $(x^2+25)(x-4)$ . FOILing out we have $x^3-4x^2+25x-100$ . There you go!

3 0

3 years ago

Of the relation

RideAnS [48]

Answer:

Domain is x and Range is y

Step-by-step explanation:

Domain-(16,-15,22,-1,-6)

Range-(5,-17,-16,-4,-14)

5 0

3 years ago

Suppose the number of insect fragments in a chocolate bar follows a Poisson process with the expected number of fragments in a 2

leonid [27]

Answer:

a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b)0.6004

c)19.607

Step-by-step explanation:

Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2

X ~ Poisson(A) where $\lambda = \frac{10.2}{200} = 0.051$

a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

$\frac{1}{4} \times 200 = 50$

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55

So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment

Let X denotes the number of grams to be eaten before another fragment is detected.

$P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004$

c)The expected number of grams to be eaten before encountering the first fragments :

$E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 gram$ s

7 0

3 years ago