Answer:
while(userNum>=1){
System.out.print(userNum/2+" ");
userNum--;
}
Explanation:
This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.
<em>import java.util.Scanner;</em>
<em>public class TestClock {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner in = new Scanner (System.in);</em>
<em> System.out.println("Enter the number");</em>
<em> int userNum = in.nextInt();</em>
<em> while(userNum>=1){</em>
<em> System.out.print(userNum/2+" ");</em>
<em> userNum--;</em>
<em> }</em>
<em> }</em>
<em>}</em>
The condition for the while statement is userNum>=1 and after each iteration we subtract 1 from the value of userNum until reaching 1 (Hence userNum>=1)
Answer:
b they have high sensitivity to surrounding sound
Explanation:
tell me it's correct or not
if it's correct so I hope it is helpful for you
but no so I am sorry
Ive done this before with success.
You will need <span>FFmpeg.</span>
https://superuser.com/questions/227338/how-to-convert-an-mkv-to-avi-with-minimal-loss
Explanation:
if you have any doubts or queries regarding the answer please feel free to ask
Answer:
Outlook as it is a common email aplication which may experience some issues
Explanation:
