I think the answer is WAN (wide area network)
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer is:
Conner has located a research source that is sponsored by a pharmaceutical company. Based on the sponsorship, Conner must be careful that the information is not <u>Biased.</u>
<u></u>
When you evaluate and use information from multiple sources, you need to evaluate the information that it must be error-free and not biased and it should be accurate information as you needed.
As in this example, Conner needs to research that the information should not be biased because the information or research source is sponsored by a pharmaceutical company and there is chances of biasedness. So, Conner must be careful that information is not biased.
English:
Recycling, in general, is good, it saves space in landfills and prevents pollution. Because some of the materials used to make the electronic piece are made with toxic ingredients its better to recycle them instead of having them end up in our oceans. Also, some pieces of electronics contain valuable metals like gold and copper. These Metals can be reused to make new better electronics with having to use the energy and money to produce new materials
Español:
El reciclaje, en general, es bueno, ahorra espacio en los vertederos y evita la contaminación. Debido a que algunos de los materiales utilizados para fabricar la pieza electrónica están hechos con ingredientes tóxicos, es mejor reciclarlos en lugar de que terminen en nuestros océanos. Además, algunos componentes electrónicos contienen metales valiosos como el oro y el cobre. Estos metales se pueden reutilizar para fabricar nuevos y mejores productos electrónicos con la necesidad de utilizar la energía y el dinero para producir nuevos materiales.
Answer:
hello your question is incomplete attached is the complete question and solution
answer : The solution is attached below
Explanation:
Below is a program named Derivations.java that creates an array with the deviations from average of another array.
