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Aloiza [94]
4 years ago
5

the height of a triangle is 2 centimetres more than the base. if the height is increased by 2 centimetres while the base remains

the same, the new area becomes 82.5 centimetres square. find the base and the height of the original triangle.
Mathematics
1 answer:
tia_tia [17]4 years ago
4 0

Answer:

Base = 11 cm

Height = 13 cm

Step-by-step explanation:

It is given that the height of a triangle is 2 centimetres more than the base.

Let x cm be the base of triangle. So height of the triangle is x+2 cm.

It is given that if the height is increased by 2 centimetres while the base remains the same, the new area becomes 82.5 centimetres square.

New height = (x+2)+2 = x+4 cm

Area of a triangle is

A=\dfrac{1}{2}\times base\times height

82.5=\dfrac{1}{2}\times x\times (x+4)

165=x^2+4x

x^2+4x-165=0

Splitting the middle term, we get

x^2+15x-11x-165=0

x(x+15)-11(x+15)=0

(x+15)(x-11)=0

Using zero product property, we get

x=-15,11

Base of a triangle can not be negative, therefore x=11.

Base = 11 cm

Height = 11+2 = 13 cm

Therefore, the base of original triangle is 11 cm and height is 13 cm.

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Answer:

  1. P₂ and x are both supplementary to N₁
  2. Q₁
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Step-by-step explanation:

1. Angles P₂ and N₁ are opposite angles of inscribed quadrilateral PMNQ, so are supplementary. Angles N₁ and N₂ form a linear pair, so are supplementary. Angles supplementary to the same angle (N₁) are congruent, hence P₂ = x ≅ N₂

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4. From the above, we know that angles N₂ and R are complementary (total 90°), so angle S₂ = 90°. Segment MS will only intersect chord PR at right angles at the midpoint of that chord.

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