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kherson [118]
3 years ago
13

PLEASE HELP FAST WILL MARK BRAINLIST

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

1, (c) 2,(c) 3,(a)

Step-by-step explanation:

1, f (x) = 2-x and f(2) = 2-2

for example f(-4) = 2-(-2) = 0

=4

3, 120° - 60° = 60

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The solutions of x² = 16x - 28 are<br> 1) -2 and -14<br> 2) 2 and 14<br> 3) -4 and -7<br> 4) 4 and 7
Allisa [31]
2 and 14
hope this helps
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3 years ago
A 2 liter drink costs $0.15 per deciliter. How much will the drink cost?
miv72 [106K]
The drink costs $3.00
7 0
3 years ago
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A bank features a savings account that has an annual percentage rate of 3.5% with interest compounded quarterly. Vanessa deposit
vazorg [7]

Answer:

APY = 0.04 or 4%

Step-by-step explanation:

Given the annual percentage rate of 3.5% that is compounded quarterly, and a principal of $6,500:

We can use the following formula to solve for the annual percentage yield (APY):

APY =  (1 + \frac{r}{n})^n - 1

where <em>r</em> = interest rate = 3.5% or 0.035

<em>           n</em> = number of compounding periods per year = 4

We can plug in the values into the equation:

APY =  (1 + \frac{r}{n})^n - 1

APY =  (1 + \frac{.035}{4})^4 - 1

APY =  (1 + 0.00875)^4 - 1

APY =  (1.00875)^4 - 1

APY = 1.03546 - 1  

APY = 0.04 or 4%        

8 0
3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
Find two numbers between 100 and 150 with HCF 24
Kazeer [188]

Answer:

120 and 144

120÷24=5

144÷24=6

7 0
3 years ago
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