I think the person on top is right
12. 90/15 is 6. 6x2 is 12.
Answer:
c.) 2 1/3
Step-by-step explanation:
i know
For the given functions, the domains are:
1) All real numbers.
2) D: x≥ -3
3) D: set of all real numbers such that x ≠ 0
4) D: 7 ≥ x ≥-7
5) All real numbers.
<h3>
How to get the domain of the given functions?</h3>
For any function, we assume that the domain is the set of all real numbers, and then we remove all the values of x that generate problems (like a denominator equal to zero or something like that).
1) f(x) = x^2 - 4
This is just a quadratic equation, the domain is the set of all real numbers.
2) f(x) = √(x + 3)
Remember that the argument of a square root must be equal to or larger than zero, so here the domain is defined by:
x + 3 ≥ 0
x≥ -3
The domain is:
D: x ≥ -3
3) f(x) = 1/x
We can assume that the domain is the set of all real numbers, but, we can see that when x = 0 the denominator becomes zero, then we need to remove that value from the domain.
Thus, we conclude that the domain is:
D: set of all real numbers such that x ≠ 0
4) f(x) = √(49 - x^2)
Here we must have:
49 - x^2 ≥ 0
49 ≥ x^2
√49 ≥ x ≥-√49
7 ≥ x ≥-7
The domain of this function is:
D: 7 ≥ x ≥-7
5) f(x) = √(x^2 + 1)
Notice that x^2 is always a positive number, then the argument of the above square root is always positive, then the domain of that function is the set of all real numbers.
If you want to learn more about domains:
brainly.com/question/1770447
#SPJ1
Answer:
a. Amplitude: 4
Period: 1
b. The maximum values occur at 
The minimum values occur at 
The zeros occur at 
Step-by-step explanation:
We can see from the graph that;
.
This implies that;
.
The amplitude is 4.
The function also completed one full cycle on the interval [0,1]
The period is
The maximum values occur at
The minimum values occur at
The zeros occur at
This is where the graph intersected the x-axis.
