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suter [353]
3 years ago
13

Evaluate the following expression. 3-2 x 33 3-1 A. 8 B. 9 C. 12 D. 15

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

is -6x to the 33'd power tims 3 - 1.       3−2x33(3)−1

Step-by-step explanation:

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Sian bought a TV in the January sales which had been reduced by 20 per cent. If she paid £290 for it, what was the original pric
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I think the anwer is 362.50
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The regular price of a shirt is $24. The sale price is $18. The sale price is what percent of the regular price?
Brrunno [24]
18=24x

\frac{18}{24}=\frac{24x}{24}

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The discount price is 75% of the original price :)
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4 years ago
Diameter of sphere is 8cm it is beaten and drawn out to a diameter of 2 mm find length of wire
m_a_m_a [10]
<span>Diameter of the sphere = 8 cm. Therefore, the radius of the sphere = 8/2 = 4 cm Volume of the sphere = 4/3 * 22/7 * 3 * 3 * 3 cu. cm. The sphere is beaten and drawn into a wire, the wire is cylinder of the diameter = 0.2 cm Area of the base of the cylinder = pi * r2 = 22/7 * 0.2 * 0.2 sq. cm volume of the wire = pi * r2 * I = 22/7 * 0.2 * 0.2 * 1 Therefore, 22/7 * 0.2 * 0.2 * I = 4/3 * 22/7 * 4 * 4 * 4 Therefore I = 4/3 * 22/7 * 4 * 4 * 4 * 7/22 * 1/0.04 I = 256/3 * 1/0.04 I = 2113 cm</span>
4 0
4 years ago
Show work
salantis [7]
The answer is 153.86:
(7 \times 7) \times \pi = 49 \times 3.14   \\ =  153.86
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153.9
6 0
4 years ago
Find all solutions to the equation (x² + 5x + 6)(x² − 3x − 4) = 0.
Soloha48 [4]

Answer:

The solutions are:

x=-2,\:x=-3,\:x=-1,\:x=4

Step-by-step explanation:

To find the solutions to the equation \left(x^2+5x+6\right)\left(x^2-3x-4\right)=0 you need to:

  • Factor \left(x^2+5x+6\right)

Break the expression into groups

x^2+5x+6=\left(x^2+2x\right)+\left(3x+6\right)

Factor out x from (x^2+2x)

x^2+2x=x\left(x+2\right)

Factor out 3 from 3x+6

3x+6=3\left(x+2\right)

x^2+5x+6=x\left(x+2\right)+3\left(x+2\right)\\\\\mathrm{Factor\:out\:common\:term\:}x+2\\\\x^2+5x+6=\left(x+2\right)\left(x+3\right)

  • Factor \left(x^2-3x-4\right)

x^2-3x-4=\left(x^2+x\right)+\left(-4x-4\right)\\\\x^2-3x-4=x\left(x+1\right)-4\left(x+1\right)\\\\x^2-3x-4=\left(x+1\right)\left(x-4\right)

Therefore

\left(x^2+5x+6\right)\left(x^2-3x-4\right)=\left(x+2\right)\left(x+3\right)\left(x+1\right)\left(x-4\right)=0

Using the Zero Factor Theorem:

5 0
4 years ago
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