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Marianna [84]
3 years ago
10

Laura bought apples to send to her friend Brad by mail. Because of mailing restrictions, the total mass of the apples cannot exc

eed 23 pounds. If the mass of each apple is 5 ounces, what is the maximum number of apples Laura can send?
A.72
B.73
C.74
D.75​
Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0

Answer:

D. 75 bc it should be that

icang [17]3 years ago
5 0

Answer:

B 73

so I had  four answer choices A 72 B 73 C 74 D 75 Someone had put that the answer was D . But,  I had this same problem on  my test I picked D and got it wrong. so clearly its not D. theses are medium apple's 1lb is 16oz I apple is 5oz 23lbs = 368oz 3 apples =15oz

take 368 and divided it by 5 you get 73.6

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Solve 12x<br>x + 16 - 1 = 0<br>​
zhuklara [117]

Answer:

xx=-0.8

Step-by-step explanation:

not sure if this is right because the 12xx is kind of strange

12xx+16-1=0
12xx+15=0
12xx=-15
12/12xx=12/-15
xx=-.8

5 0
2 years ago
Find the slope of the line. Use the two points shown.
stellarik [79]

Answer:

The slope is 2.

Step-by-step explanation:

slope = rise/run

= 1-(-5) / 2-(-1)

= 6/3 = 2

Therefore, the slope is 2.

5 0
3 years ago
Which of the following pairs of numbers contain like fractions?
saveliy_v [14]
Like fractions are fractions that have the same denominator. In option D, both denominators are 7. Therefore, they are like fractions.
7 0
4 years ago
Read 2 more answers
5. An um contains 50 marbles, 40 blue ones and
irinina [24]

Answer:

A. 40/100 = 2/5 b. 5/95 (i think)

Step-by-step explanation:

I hope it helps

4 0
3 years ago
Someone get me the answers ASAP!! thank you
Virty [35]
This relies on the distance formula like number two, which you answered correctly.

I think it's helpful to draw this out. I made a digital drawing on GeoGebra (free) and connected the vertices. Now, to find the area, we need the side lengths to start. This program actually gives you the side lengths as well, but pretending we don't already have that, you can plug in each vertex into the distance formula.

a =  \sqrt{(-4-3)^{2}+ (2-2)^{2}} = 7

b =  \sqrt{(3-3)^{2}+(2-(-5))^{2}} = 7

c =  \sqrt{(3-(-4))^{2}+(-5-(-2))^{2}} =  \sqrt{58}

d =  \sqrt{(-4-(-4))^{2}+(2-(-2))^{2}} = 4

So, unfortunately, we don't have a regular polygon, so this isn't simply length times width. But we can easily cut this into a rectangle and a triangle, whose areas are much easier to find (see second image).

The area, A, of a triangle is \frac{1}{2} B * h and the area of a rectangle is simply l * w. So the base of our triangle is 7 units, and the height is 3 units, so the area is 10.5 units squared. The length of our rectangle is 7 units, and the width is 4 units, so the area is 28 units squared.

A = A_{triangle} + A_{rectangle} = 10 \frac{1}{2}+28 = 38\frac{1}{2} units squared.



I would like to clarify that you do not actually need to find all those distances for this problem. Once it's drawn out, it's fairly easy to tell.

7 0
4 years ago
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