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ra1l [238]
3 years ago
12

How to find the square root of 56 without using a calculator

Mathematics
2 answers:
Olegator [25]3 years ago
7 0
There an old algorythmic method similar to long division:-
          
                 7 .   4   8   3
              -----------------
              ) 56. 00 00 00
          7  ) 49
              ) ---
     144   )   7 00
             )    576   
                  ----
  148 8 )     12400
           )      11904
                  -------
          )       496 00
1496 3  )    44889    

THis gives the square root as 7.48  to the nearest hundredth

 
photoshop1234 [79]3 years ago
5 0
Do a factor tree (i think that is what they called it)

56
4 14
22 2 7

2radical 14
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A performer excepts to sell 5,000 tickets for an upcoming concert. They want to make a total of $311,000 in sales from these tic
Katena32 [7]
The answer is 435,400
Explanation :
If 5000 tickets = 311,000
And 7000 tickets = x
Cross multiplication method
Then x = 7000 *311,000 / 5000
X= 435,400
4 0
3 years ago
The drama department is raising money to purchase a new lighting system for the auditorium
Lelechka [254]

Answer:

D

Step-by-step explanation:

the $90 per week multiplied by x amount of weeks + the $450 that they have already raised will equal the $1350 they need

5 0
3 years ago
Simplify and evaluate. 4−2
Nikitich [7]
4-2 = 2-1
You can do the evaluating part.
3 0
3 years ago
This is for algebra 1
allsm [11]
X+y=12 -- 1
3x+2y=29 -- 2

(1)x2
2x+2y=24 -- 1
(2)-(1)
x=5

Sub x into 1
x+y=12
5+y=12
y=7

Her two numbers are 5 and 7
3 0
3 years ago
Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi
ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

E = \{ x \in \Omega: x \text{ starts with the letter J}\}

So, we have

E = \{\text{January},\ \text{June},\ \text{July}\}

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0
3 years ago
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