Question

In your dresser are five blue shirts, three red shirts,

Answer 1

First, add all of the shirts together (5+3+2) which equals 10 shirts in total.

a) The probability of selecting a red shirt would be 3/10 or 30% chance.

b) The probability that a black shirt would not be selected would be 8/10 or 80% chance.

Answer 2

a) What is the probability of randomly selecting a red shirt?

-> Probability can be solved with wanted outcomes divided by total outcomes

$\frac{3}{5+3+2} =\frac{3}{10}$

Answer: $\frac{3}{10}$ or 30%

b) What is the probability that a randomly selected shirt is not

black?

-> Probability can be solved with wanted outcomes divided by total outcomes

$\frac{(5+3+2)-2}{5+3+2} =\frac{10-2}{10} =\frac{8}{10}=\frac{4}{5}$

Answer:  $\frac{4}{5}$ or 80%

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