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Sladkaya [172]
3 years ago
13

In your dresser are five blue shirts, three red shirts,

Mathematics
2 answers:
Ugo [173]3 years ago
8 0
First, add all of the shirts together (5+3+2) which equals 10 shirts in total.

a) The probability of selecting a red shirt would be 3/10 or 30% chance.

b) The probability that a black shirt would not be selected would be 8/10 or 80% chance.
Katarina [22]3 years ago
5 0

a) What is the probability of randomly selecting a red shirt?

-> Probability can be solved with wanted outcomes divided by total outcomes

\frac{3}{5+3+2} =\frac{3}{10}

<u>Answer</u>: \frac{3}{10} or 30%

b) What is the probability that a randomly selected shirt is not

black?

-> Probability can be solved with wanted outcomes divided by total outcomes

\frac{(5+3+2)-2}{5+3+2} =\frac{10-2}{10} =\frac{8}{10}=\frac{4}{5}

<u>Answer</u>:  \frac{4}{5} or 80%

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

     ★ Also please leave the rating you think I deserve (It helps other users as well as myself)

- Heather

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motikmotik

Just replace x with 1.

4-3+2(1-1)

then solve

4-3+2(0)

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1 is the answer.

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4 years ago
Solve the graph to find
Juliette [100K]

Answer:

Step-by-step explanation:

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8 0
3 years ago
A car leaves an intersection traveling west. Its position 4 sec later is 18 ft from the intersection. At the same time, another
Evgen [1.6K]

Answer:

The rate at which the distance between the two cars is changing is;

15.53 ft/sec.

Step-by-step explanation:

To solve the question, we note that

Position of car A 4 s after start of motion, w = 18 ft west,

Position of car B 4 s after start of motion, n = 27 ft north

Therefore

The distance between the two cars at the 4 s instance is

d² = w² + n²

d² = 18² + 27² = 1053 ft² and

d = 32.45 ft

The rate at which the distance between the two cars is changing is given by;

Differentiating both sides of the equation, d² = w² + n², with respect to t as follows.

\frac{dd^2}{dt} = \frac{dw^2}{dt} + \frac{dn^2}{dt} \Longrightarrow 2 d\frac{dd}{dt} = 2w\frac{dw}{dt} + 2n\frac{dn}{dt}

It is given that the speeds of car A and car B at the 4 second instant are 7 ft/sec and 14 ft/sec, respectively

That is;

\frac{dw}{dt} = 7\frac{ft}{sec} and \frac{dn}{dt} = 14\frac{ft}{sec}

Substituting the values of speed in the equation of rate of change gives

2 d\frac{dd}{dt} = 2w\frac{dw}{dt} + 2n\frac{dn}{dt}\Longrightarrow d\frac{dd}{dt} = w\frac{dw}{dt} + n\frac{dn}{dt}

d\frac{dd}{dt} = w\frac{dw}{dt} + n\frac{dn}{dt} \Longrightarrow 32.45\frac{dd}{dt} = 18\times 7 + 27\times 14 = 504

32.45\frac{dd}{dt}  = 504

\frac{dd}{dt}  = \frac{504}{32.45}  = 15.53 \frac{ft}{sec}

The rate at which the distance between the two cars is changing = dd/dt = 15.53 ft/sec.

7 0
3 years ago
Read 2 more answers
The government of the Republic of Lemon Island plans to transform their lemon-based
sattari [20]

Step-by-step explanation:

dy/dt = (A − Be^(-t/5)) y

(a) Find the general solution by separating the variables and integrating.

dy / y = (A − Be^(-t/5)) dt

dy / y = [A + 5B (-⅕ e^(-t/5))] dt

ln |y| = At + 5B e^(-t/5) + C

y = e^(At + 5B e^(-t/5) + C)

y = Ce^(At + 5B e^(-t/5))

(b) As t approaches infinity, dy/dt approaches Ay.  The rate of growth, A, is triple the initial rate of growth 0.02, so A = 0.06.

When t = 0, dy/dt = (A − B)y.  The rate of growth, A−B, is 0.02.  We know A = 0.06, so B = 0.04.

(c) Given that A = 0.06, B = 0.04, and y(0) = 50×10⁶ − 10×10⁶ = 40×10⁶:

40×10⁶ = Ce^(0.06(0) + 5(0.04) e^(-0/5))

40×10⁶ = Ce^(0.2)

C = 40×10⁶ e^(-0.2)

y = 40×10⁶ e^(-0.2) e^(0.06t + 0.2 e^(-t/5))

y = 40×10⁶ e^(-0.2 + 0.06t + 0.2 e^(-t/5))

(d) If A = 0.02 and B = 0, and there is no transformation (y(0) = 50×10⁶), then:

50×10⁶ = Ce^(0.02(0) + 0)

50×10⁶ = C

y = 50×10⁶ e^(0.02t)

Comparing to the answer from part (c):

40×10⁶ e^(-0.2 + 0.06t + 0.2 e^(-t/5)) = 50×10⁶ e^(0.02t)

e^(-0.2 + 0.04t + 0.2 e^(-t/5)) = 5/4

-0.2 + 0.04t + 0.2 e^(-t/5) = ln(5/4)

-5 + t + 5e^(-t/5) = 25 ln(5/4)

t + 5e^(-t/5) = 5 + 25 ln(5/4)

Solve with a calculator:

t = 9.886

The transformed economy surpasses the untransformed economy in the 10th year.

(e) In year t=5, the size of the transformed economy is:

y = 40×10⁶ e^(-0.2 + 0.06(5) + 0.2 e^(-5/5))

y = 47.6×10⁶

The percent growth is:

(47.6×10⁶ − 40×10⁶) / 40×10⁶ × 100% = 19%

The growth rate is greater than 4%, so the current government can expect to be reelected.

7 0
3 years ago
List three different combinations of coins, each with a value of 140% of a dollar
Agata [3.3K]

Answer:

1) 14 dimes

2) 5 quarters 3 nickels

3) 140 pennies

4) 28 nickels

5) 4 quarters 4 dimes

6) 10 dimes 4 nickels

Step-by-step explanation:

140% = $1.40

5 0
3 years ago
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