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kiruha [24]
3 years ago
13

Macar+acar+car+ar+r=VACAR urgent please

Mathematics
1 answer:
USPshnik [31]3 years ago
7 0

1 Simplify exponent
ma2cr+acar+car+ar+r=vacar

2 Simplify exponent
ma2cr+a2cr+car+ar+r=vacar

3 Factor out the common term r
r(ma2c+a2c+ca+a+1)=vacar

4 Cancel r on both sides
ma2c+a2c+ca+a+1=vaca

5 Subtract a2c from both sides
ma2c+ca+a+1=vaca−a2c

6 Factor out the common term ca
ma2c+ca+a+1=ca(va−a)

7 Subtract ca from both sides
ma2c+a+1=ca(va−a)−ca

8 Factor out the common term ca
ma2c+a+1=ca(va−a−(1))

9 Subtract a from both sides
ma2c+1=ca(va−a−1)−a

10 Factor out the common term a
ma2c+1=a(c(va−a−1)−1)

11 Subtract 1 from both sides
ma2c=a(c(va−a−1)−1)−1

12 Divide both sides by a2
mc=a(c(va−a−1)−1)−1a2

13 Divide both sides by c
m=a(c(va−a−1)−1)−1a2c
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Louisa worked 2 1/2 times as many hours as Sally worked. Sally worked 10 3/4 hours. How may hours did Louisa work last week ?
frosja888 [35]

Answer:215/8

I hope that this answer help you get your homework done ✅

3 0
3 years ago
Marie mixes 40 liters of 12% acid solution with a 32% acid solution to make a 16% acid solution. How many liters of 32% solution
aleksandrvk [35]
We let the amount of 32% acid solution added to be X ,
Firstly, 40 of 0.12 conc. , = 4.8L of acid, and 35.2L non acid
For ever 1 L of 32% acid we add in we get 0.32L of acid and + 0.68L non Acid, 
So we formulate an equation
(4.8+0.32X) / (40+X) = 16/100
(4.8+0.32X) = 0.16(40+X) =6.4+0.16X
0.16X = 1.6
X =10
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4 0
3 years ago
Write the expression using exponents. (-5)(-5)(-5)(-5)
Luba_88 [7]

Answer:

(-5)^4

Step-by-step explanation:

^4 is the exponent

You must have the parentheses.

7 0
3 years ago
What is the amplitude of sin ?
sp2606 [1]

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

\displaystyle \large{ y = A \sin(bx  -  c) + d}

  • A = amplitude
  • b = period = 2π/b
  • c = horizontal shift
  • d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

\displaystyle \large{y = 2 \sin x}

Refer to the equation above:

  • Amplitude = 2
  • b = 1 and therefore, period = 2π/1 = 2π
  • c = 0
  • d = 0

Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

6 0
3 years ago
HELP ME PLZZ I AM GIVING 40 POINTS
Alexxandr [17]

Answer:

I think the answer is B BBbBBb

8 0
3 years ago
Read 2 more answers
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