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Black_prince [1.1K]
3 years ago
9

The shortest distance between two points is what?

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0
The shortest distance between two points would be a straight line
swat323 years ago
6 0

Answer:Geodesic

Step-by-step explanation:K12

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A table has an area of 12 ft squared and a perimeter of 16 ft. What are the dimensions of the table?
Likurg_2 [28]
P=2x+2y, y=(p-2x)/2

a=xy, using y found above in this equation gives you:

a=(px-2x^2)/2  we are told a=12 and p=16 so

12=(16x-2x^2)/2

24=16x-2x^2

2x^2-16x+24=0

2x^2-12x-4x+24=0

2x(x-6)-4(x-6)=0

(2x-4)(x-6)=0

2(x-2)(x-6)=0

So the table is 2 ft by 6 ft.
7 0
3 years ago
Read 2 more answers
3 elevenths divided by 3 elevenths
WARRIOR [948]

Answer:

1

Step-by-step explanation:

3/11 *3/11

2nd 3/11 flips over. Then multiply. Then u get 33/33 which equals 1

8 0
2 years ago
Consider the following system of equations:
IrinaK [193]

Answer:

x = 6 ; y = -9

Step-by-step explanation:

8 x + 2 y = 30  ..........equ No 1

7 x + 2 y = 24......... equ No 2

8 x = 30 - 2y

∴ x =\frac{ 30 - 2 y}{8}

substituting the value of x in equ No 2

7 \frac{30 - 2 y}{8} + 2 y = 24

7 ( 30 -2 y) + 2 y × 8 = 24 × 8

7 × 30 - 14 y + 16 y = 192

210 + 2 y = 192

2 y = 192 - 210

2 y = - 18

∴ y = - 9

put y = -9 , 8 x = 30 - 2 y

        8 x = 30 - 2 ( -9)

    8 x = 30 - ( -18)

  8 x = 48

∴ x = 6

x = 6 ; y = -9

3 0
3 years ago
Q = 15<br> a = 16<br> What would you do with q and a to get 240?
ch4aika [34]

You multiply Q and a to get 240, because 15 x 16 = 240.

6 0
3 years ago
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
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