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Zielflug [23.3K]
3 years ago
13

To get an A in a course, you must have an average of at least 90% on four tests worth 100 points each. Your scores so far are 85

, 94, and 84. What must you score on the fourth test to get an A in the course?
Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer:

A score of 117 is needed, which Is not possible since the test is over 100.

Step-by-step explanation:

The other 3 scores are 85, 94,84 . Let's x be the 4th score he must score.

Therefore ( 85 + 94 + 84 + X)/4 =95

Then 263+X /4 =95

Cross mutiplying 4*95=263+X

Therefore X= 380-263

X= 117 which is not possible since the test score is over 100.

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S t are positive integers
Sindrei [870]

Given:

The expanded form of (x+s)(x-t) is x^2+Kx-40.

Where, s, t, K are positive integers.

To find:

The smallest possible value of K.

Solution:

The expanded form of (x+s)(x-t) is x^2+Kx-40. It means,

(x+s)(x-t)=x^2+Kx-40

x^2-tx+sx-st=x^2+Kx-40

x^2+(s-t)x-st=x^2+Kx-40

On comping both sides, we get

K=s-t              ...(i)

K is a positive integer if s>t.

And

st=40

The factor pairs of 40 are (1,40), (2,20), (4,10), (5,8), (8,5), (10,4), (20,2) and (40,1).

Since s>t, therefore the possible values for (s,t) are (8,5), (10,4), (20,2) and (40,1).

Using (i), find the value of K for each factor pair.

K=8-5=3  

K=10-4=6      

K=20-2=18          

K=40-1=39          

Therefore, the smallest possible value of K is 3.

3 0
3 years ago
Nia solved the equation -1.98 = 5.2v + 13.1. Her answer was v = -2.9. She is fairly confident about her answer, but wants to do
valina [46]

Answer:

substitute for v, when v = -2.9

Step-by-step explanation:

-1.98=5.2v+13.1

subtract 13.1 on both sides.

-15.08=5.2v

divide by 5.2 to isolate v

\frac{-15.08}{5.2} = \frac{5.2v}{5.2}

-2.9=v

substitute for v

-1.98=5.2(-2.9)+13.1

-1.98=-15.08+13.1

-1.98=-1.98

6 0
3 years ago
Evaluate for M/NP = 10, N = -5, and P = -2
Slav-nsk [51]
Hope this helps you..!!

3 0
3 years ago
Wich time of line are shown in the figure
shtirl [24]

Solution

Step 1

Two distinct lines intersecting each other at 90° or at right angles are perpendicular to each other.

Hence apply this to question 8 the type of lines shown in the figure is perpendicular lines. Option C

Step 2

To explain this as stated above line A and line B intersect each other at a right angle hence line A and B are perpendicular lines. The line segments are seen below.

5 0
1 year ago
you want to determine how many students consider math to be their favorite subject. you randomly survey 75 students. 33 students
Burka [1]
No, is not valid.
33 is 44% of 75
33 ÷ 75 = 0.44
0.44 = 44%
4 0
3 years ago
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