45 times gives me a 100

2. angle ABE = angle MNP <br><br> Write another valid congruency statement:

Free_Kalibri [48]

Given:

$\Delta ABE\cong \Delta MNP$

To find:

The congruent angles and sides, then find the another valid congruency statement.

Solution:

We have,

$\Delta ABE\cong \Delta MNP$

We know that, corresponding parts of congruent triangles are congruent (CPCTC).

Using CPCTC, we get

Angles:

$\angle A\cong \angle M$

$\angle B\cong \angle N$

$\angle E\cong \angle P$

Sides:

$AB\cong MN$

$BE\cong NP$

$AE\cong MP$

The another congruent statement is $\Delta BEA\cong \Delta NPM$ .

Therefore, the required table is

Angles Sides

$\angle A\cong \angle M$ $AB\cong MN$

$\angle B\cong \angle N$ $BE\cong NP$

$\angle E\cong \angle P$ $AE\cong MP$

The another congruent statement is $\Delta BEA\cong \Delta NPM$ .

4 0

3 years ago

Four friends went bowling one afternoon. Use the table that shows the bowling data

Kaylis [27]

Answer: Carson's average points in each game = 122

Jana's average points in each game = 104.4

Step-by-step explanation:

By the given table,

1) The total points Carson get in the game = 366,

He played games = 3,

⇒ His average point in each game = Total points he get/ total game he play

= 366/3

= 122

2) Now, The total points Jana get in the game = 522,

She played games = 5,

⇒ Her average point in each game = Total points she get/ total game she play

= 522/5

= 104.4

6 0

2 years ago

Given the graphed function below, which of the following ordered pairs are

Paul [167]

Answer:

B

Step-by-step explanation:

On the inverse, you switch the x and y. So on the function there is point (-2,-11) and on the inverse there is point (-11,-2)

7 0

3 years ago

Read 2 more answers

Last year new Russell traveled 2378 km and 126 meters to Iceland on vacation. This year she plans to travel 5698 km and 456 m to

Natali5045456 [20]

Answer plus work. 8,076km and 582m

3 0

3 years ago

The following data comparing wait times at two rides at Disney are listed below: Position Pirates Splash Mountain Sample Size 32

myrzilka [38]

Answer:

a) $(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968$

$(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788$

b) $t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10$

Step-by-step explanation:

Data given and notation

$\bar X_{A}=14.68$ represent the mean for Pirates

$\bar X_{B}=18.77$ represent the mean for Splash Mountain

$s_{A}=11.87$ represent the sample standard deviation for the sample Pirates

$s_{B}=16.79$ represent the sample standard deviation for the sample Slpash Mountain

$n_{A}=32$ sample size selected for Pirates

$n_{B}=30$ sample size selected for Splash Mountain

$\alpha=0.02$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a

The confidence interval would be given by:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}$

The degrees of freedom are given by:

$df = n_A +n_B -2 = 32+30-2 = 60$

Since we want 98% of confidence the significance level is $\alpha =1-0.98 =0.02$ and $\alpha/2 =0.01$ , we can find in the t distribution with df =60 a critical value that accumulates 0.01 of the area on each tail and we got:

$t_{\alpha/2}= 2.39$

And replacing we got for the confidence interval:

$(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968$

$(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788$

Part b

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the means are equal, the system of hypothesis would be:

Null hypothesis: $\mu_{A} = \mu_{B}$

Alternative hypothesis: $\mu_{A} \neq \mu_{B}$

the statistic is given by:

$t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10$

6 0

2 years ago