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3 years ago

4. The distance from lan's home to the museum

Mathematics

1 answer:

Hitman42 [59]3 years ago

4 0

Answer:

no bc 2640 yards in feet is 7920

Step-by-step explanation:

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325 meters in 28 secs

oksano4ka [1.4K]

Answer:

325 / 28 = ?

Step-by-step explanation:

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3 years ago

PLEASE NEED HELP

enot [183]

Answer is A hope I helped her it

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3 years ago

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What is the total in this sequence - 5 + 10 + ....... + 550 + 555?

deff fn [24]

◆ Arithmetic Progressions ◆

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4 years ago

If f(x) = 3x^5 + 4x^4 + 5, then what is the remainder when f(x) is divided by X + 3?

Musya8 [376]

Answer:

remainder: -400

Explanation:

$\sf f(x) = 3x^5 + 4x^4 + 5$

divided by x + 3

x + 3 = 0

x = -3

insert x = -3 in the function

$\sf f(x) = 3(-3)^5 + 4(-3)^4 + 5$

$\sf f(-3) = -400$

5 0

3 years ago

The length of a rectangular pool is to be four times its width and a sidewalk 6ft wide will surround the pool. If a total area o

natita [175]

Answer:

52 feet by 13 feet.

Step-by-step explanation:

Given:

The length of a rectangular pool is to be four times its width.

Sidewalk is 6 feet wide will surround the pool.

If a total area of 1600 square feet has been set aside for the area of the pool and the sidewalk.

Question asked:

What are the dimensions of the pool?

Solution:

Let width of a rectangular pool = $x$

Then the length of a rectangular pool will be = $4x$

$Area\ of \ rectnagle= length\times breadth$

$=x\times4x\\ \\ =4x^{2}$

Combined length of pool and the sidewalk = length of pool + width of sidewalk + width of sidewalk

Combined length of pool and the sidewalk = $4x+6+6=4x+12$

Similarly, Combined width of pool and the sidewalk = $x+6+6=x+12$

Combined area of pool and the sidewalk = 1600

$Combined\ lengthh\times Combined\ r=breadth=1600\\ \\ (4x+12)(x+12)=1600\\ \\ 4x(x+12)+12(x+12)=1600\\ \\ 4x^{2} +48x+12x+144=1600\\ \\ 4x^{2} +60x+144=1600$

Subtracting both sides by 144

$4x^{2} +60x=1456\\ \\ 4x^{2} +60x-1456=0\\ \\ Taking\ 4\ as\ common\\ \\ x^{2} +15x-364=0\\ \\ x^{2} +28x-13x-364=0\\ \\ x(x+28)-13(x+28)=0\\ \\ x+28=0,x-13=0\\ \\ x=-28,x=13$

Since dimensions can never be in negative, hence $x=13$

Width of a rectangular pool = $x$ = 13 feet

The length of a rectangular pool will be = $4x$ = $4\times13=52\ feet$

Therefore, the dimensions of the pool are 52 feet by 13 feet.

8 0

3 years ago