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andrew11 [14]
3 years ago
12

A plastic container holds 3 red balls, 2 green balls, and 3 yellow balls. What is the probability of choosing a green ball, repl

acing it, and then choosing a yellow ball?
Mathematics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

0.09375

Step-by-step explanation:

the total number of balls = 3 + 3 + 2 = 8

Let p be the probability of choosing a green ball, replacing it, and then choosing a yellow ball.

p=p\left( \text{choosing a green ball} \right)  +p\left( \text{choosing a yellow ball} \right)

  =\frac{2}{8} \times \frac{3}{8}

  =\frac{6}{64}

  = 0.09375

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