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svetlana [45]
4 years ago
8

Use the number line​ below, where RS equals 3 y plus 2 ​, ST equals 2 y plus 7 ​, and RT equals 10 y minus 11 .

Mathematics
2 answers:
vladimir2022 [97]4 years ago
7 0

Use the number line​ below, where RS=7y+2​, ST=5y+7​, and RT=14y−3. a. What is the value of​ y? b. Find​ RS, ST, and RT.

docker41 [41]4 years ago
4 0
3y + 2 + 2y + 7 = 10y - 11
5y + 9 = 10y - 11
20 = 5y
4 = y

RS = 14
ST = 15
RT = 29
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Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form. A) y – 1 = 2(x – 3) B) y – 3
fomenos
So point slope form is y=mx+b where m=slope and b=y intercept so

in (x,y) form
one solution is x=1 and y=3, also slope is 2 so
m=2
subsitute
3=2(1)+b
3=2+b
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equation is
y=2x+1

tricky answers so simplify them
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4 years ago
Drag each equation to show if it could be a correct first step to solving the equation 9(x + 2) = 90
irakobra [83]
No signs of draggin stuff

so PEMDAS

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3 years ago
I'm marking answers as brainliest ----- One of the vertices for this linear programming problem is __________. ----- (1,2) (3.5,
Travka [436]

Answer:

(0,2.3)    if only one choice expected.

(0,2.3) and (0,0)  if "all that apply" expected, since (0,0) is also a vertex of the green region.

Step-by-step explanation:

From the attached diagram, the given answer optsions are shown in brown.

The red line shows the optimal combinations of the two variables, hence a maximization problem.

Out of the four answer options, two coincide with a vertice of the valid region (shown in green), namely (0,0) and (0, 2.3).

Out of the two indicated options which correspond to a vertex, the origin (0,0) is usually ignored for a maximization problem, which leaves us with (0,2.3) as the answer.

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3 years ago
Boris chooses three different numbers the sum of the three numbers is 36 one of the numbers is a cube number the other two numbe
OlgaM077 [116]

Answer:

3,4,5

Step-by-step explanation:

Here, we need to asume that the values are integers, as if not, there will be infinite solutions.

Lets go by parts:

The 1st number is a cubic, lets call it A

The second is a factor of 20, lets call it B. The same for the 3rd, call it C.

So, A + B+ C = 36

There are no many factors of 20, those are the numbers that when multiplied gives as the value of 20. Those are 1, 2, 4, 5, 10 and 20. So, B and C are some of these numbers.

Then, we know A if less than 36, other way the whole sum will be greater than 36. How many cubic number with integer cubic roots are less than 36? Well, lets guess:

1^3 = 1 -> valid, as it is less than 36

2^3 = 8 -> valid, as it is less than 36

3^2 = 27 -> valid, less than 36

4^3 = 64 -> not valid, as it is greater than 36

So, A ir 1, 2 or 3.

If A is 1, then B+C needs to be 35. But, from the factors of 20 that we listed, there are no combinations of 2 numbers that sum 35. So, A CAN'T be 1.

If A = 2, then we have:

8 + B + C = 36

B + C = 28

And again, there are not combinations of two factors of 20 that sum 28 (try yourself).

If A=3:

27 + B + C = 36

B +C = 9

And we have a winner!!! If B=4 and C=5 (or viceversa C=4 and B=5)

27 + 4 + 5 = 36

So, A=3, B=4 and C=5 or A=3, C=4 and B=5 are solutions.

3 0
4 years ago
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