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3 years ago

If the perimeter of isosceles ΔABC is 45 and side AC is 11, give one possible value for the length of side BC.

Mathematics

1 answer:

solmaris [256]3 years ago

5 0

Hello from MrBillDoesMath!

Answer:

Discussion:

In ΔABC side AC is 11, but as the triangle is isosceles the other leg also has length 11. Let the third, unknown side, be called x. Then

11 + 11 + x = Perimeter = 45.

11 + 11 + x = 45 => as 11 + 11 = 22

22 + x = 45 => subtract 22 from both sides

x = 45 -22 = 23

Thank you,

MrB

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==================================================

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3 years ago

Your third-grade classroom has 32 boys and girls. Two-thirds of the boys and three-fourths of the girls are going on a field tri

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Answer: The ratio of boys to girls would be 3 : 5 .

Step-by-step explanation:

Since we have given that

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Fraction of boys are going on a field trip = $\dfrac{2}{3}$

Fraction of girls are going on a field trip = $\dfrac{3}{4}$

Number of children left = 9

Let the number of boys be 'b'.

Let the number of girls be 'g'.

According to question, it becomes ,

$b+g=32------------(1)\\\\32-9=\dfrac{2}{3}b+\dfrac{3}{4}g\\\\23=\dfrac{2b}{3}+\dfrac{3g}{4}-------------(2)$

From eq(1), we get that g = 32-b

So, it becomes,

$\dfrac{2}{3}b+\dfrac{3}{4}(32-b)=23\\\\\dfrac{2}{3}b+24-\dfrac{3}{4}b=23\\\\\dfrac{2}{3}b-\dfrac{3}{4}b=23-24=-1\\\\\dfrac{8b-9b}{12}=-1\\\\\dfrac{-b}{12}=-1\\\\b=-1\times -12\\\\b=12$

so, number of girls would be 32 - b = 32 - 12 = 20

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Therefore, the ratio of boys to girls would be 3 : 5 .

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