Hi, thank you for posting your question here at Brainly.
The general equation of a horizontal ellipse is
(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.
If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,
2b = 16
b = 8
b^2 = 64
The distance between the two foci is 2c. Thus,
2c = 12
c = 6
c^2 = 36
Then, a2 = 64 + 36 = 100. Substituting to the general equation:
x^2/100 + y^2/64 = 1
Answer:
That would be 2/3
Step-by-step explanation:
1/3 would be the first line after 0 and 3/3 is = to 1 so the correct answer is 2/3
To write it in function notation you'll convert it into a function, substituting y by f(x):
y = 3x - 8 = f(x) = 3x - 8
Hope it helped,
BioTeacher101
Based on the positions of angles AFC and EFC, the relationship between them is a Complimentary angle.
<h3>How are AFC and EFC related?</h3>
Angles AFC and EFC are complimentary angles because complimentary angles are angles that add up to 90 degrees.
Looking at the shape, Line FC divides the right angle to create angles AFC and EFC so when these are added together, they equal 90 degrees.
In conclusion, angles AFC and EFC are complimentary.
Find out more on complimentary angles at brainly.com/question/20728641.
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Answer:
A. m^2+7m+10=0
Step-by-step explanation:
This is a problem in pattern matching, and in substituting a variable for a pattern.
(x^2+3)^2 +7x^2 +21 = -10 . . . . . . given
(x^2 +3)^2 +7(x^2 +3) = -10 . . . . . factor the last two terms
m^2 +7m = -10 . . . . . . . . . . . . subsitute m for x^2 +3
m^2 +7m +10 = 0 . . . . . . . . add 10 to both sides; matches A
