How do I solve 6x (y-x)
1 answer:
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Answer:
length of other leg = 20'
Step-by-step explanation:
Given:
One leg of triangle let it be base of triangle = 21'
Hypotenuse = 29'
To Find:
Third leg =perpendicular = ?
Solution:
Given is a right angled triangle with two of its sides given to us
We have Pythagoras theorem for right angled triangle and according to it
Pythagoras theorem is
for a right angled triangle
(hyp) ² = (perp)²+(base)²
We have the values of hyp and base
putting them in the equation we get
(29) ² = (perp) ²+(21) ²
841 = (perp) ² + 441
subtracting 441 from both sides we get
841 - 441 = (perp) ² + 441 - 441
400 = (perp)²
or
(perp) ²=400
Taking square root of both sides
it gives us
perp = ± 20'
As it is length and it can not be negative so
perp = 20'
or
length of other leg = 20'
Answer:
Width is 3x+7 units
Step-by-step explanation:
In the attached file
