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statuscvo [17]
3 years ago
9

Find the value of -5 - (- 6)-(-3)=

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0

Answer: -5-(-6)-(-3)= 4

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Sent a picture of the solution to the problem (s).

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X-5y=-15x−5y=−15x, minus, 5, y, equals, minus, 15 Complete the missing value in the solution to the equation. (-5,(−5,left paren
Y_Kistochka [10]

Answer:

<h2>The missing value is 2. The coordinate will be (-5, 2)</h2>

Step-by-step explanation:

The question is not properly written. Find the correct question below.

If x – 5y = -15 . Complete the missing value in the solution to the equation (-5, ____)

Let the coordinate of the variables be (x, y). Comparing the coordinates (x, y) with the given coordinate (-5, __), we will discover that x = -5. To get the y coordinate, we will substitute x = -5 into the given expression as shown;

If x – 5y = -15

-5 - 5y = -15

Adding 5 both sides

-5-5y+5 = -15+5

-5y = -10

Dividing both sides by -5;

-5y/-5 = -10/-5

y = 2

<u>Hence the missing value in the solution of the equation is 2</u>. The coordinate will be (-5, 2)

3 0
3 years ago
The Arnold family arrived at the beach at
AlekseyPX

Answer:

13:30 military time, 1:30 normal time.

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Solve for x.<br><br> 4x + 6 = 38<br><br> What is the answer?
sertanlavr [38]

Answer:

x = 8

Step-by-step explanation:

We solve the equation:

4x + 6 = 38

4x = 38 - 6

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The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog. If the
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Answer:

Step-by-step explanation:

A direct variation equation is of the form

y = kx,

where, in words, it reads "y varies directly with x" or "y varies directly as x". In order to use this as a model, we have to have enough information to solve for k, the constant of variation. The constant of variation is kind of like the slope in a straight line. It rises or falls at a steady level; it is the rate of change.

We have that a vet gives a dose of three-fifths mg to a 30 pound dog. If the dose varies directly with the weight of the dog, then our equation is

d = kw and we need to find k in order to have the model for dosing the animals.

\frac{3}{5} =k(30)

Divide both sides by 1/30 to get k alone.

(\frac{1}{30})(\frac{3}{5})=k and

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Our model then is

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This means that for every pound of weight, the dog will get one-fiftieth of a mg of medicine.

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