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Jobisdone [24]
3 years ago
14

Subtraction with unlike denominators 3/4-3/8

Mathematics
1 answer:
sp2606 [1]3 years ago
5 0
First, you need to find a common denominator. In this case, it's 8. So, to get 4 to 8, multiply 3/4 by 2/2. You'll get 6/8. Then, 6/8-3/8=3/8
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Using the Following Image, solve for x
OlgaM077 [116]

Answer:

x = 2

Step-by-step explanation:

x + 1 + 4 = 2x + 3

x + 5 = 2x +3

x + 2 = 2x

2 = x

x = 2

5 0
2 years ago
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HELP PLZ DUE RN BRAINIEST TO WHOEVER RIGHT
stealth61 [152]

Answer:

x = 11, -1

Step-by-step explanation:

First, let's identify what the quadratic formula is:

x = [-b ± √(b² - 4(a)(c))] / 2

Our equation is written in standard form:

ax² + bx + c = 0

x² - 10x - 11 = 0

Let's plug in what we know.

x = [-(-10) ± √((-10)² - 4(1)(-11))] / 2

Evaluate the exponent.

x = [-(-10) ± √(100 - 4(1)(-11))] / 2

Simplify the negatives.

x = [10 ± √(100 - 4(1)(-11))] / 2

Multiply.

x = [10 ± √(100 + 44)] / 2

Simplify the parentheses.

x = [10 ± √(144)] / 2

Simplify the radical (√)

x = [10 ± 12] / 2

Evaluate the ±.

x = [10 + 12] / 2

x = [22] / 2

x = 11

or

x = [10 - 12] / 2

x = [-2] / 2

x = -1

Your answers are x = 11, -1

Hope this helps!

8 0
3 years ago
X
Oxana [17]
I don’t quite understand this question since it’s all spaced out and there’s no picture but since domain is x/the indecent variable, “x = -6, -1, 0, 3” (the first answer choice” is correct
3 0
3 years ago
Situation D: Suppose that, in a one-minute period during an electrical storm, the number of lightning strikes on a radar antenna
Crank

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

In this question:

\mu = 2.40

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177

21.77% probability that the antenna will be struck exactly once during this time period.

3 0
3 years ago
Given that ∠CEA is a right angle and bisects ∠CEA, which statement must be true?
loris [4]
Given that ∠CEA is a right angle which has been bisected by BE, then:
∠CEB=∠BEA
thus each angle will be complementary to each other, hence the size will be:
90/2=45°
hence the correct statement.
<span>m∠CEB = 45°</span>
8 0
3 years ago
Read 2 more answers
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