Subtraction with unlike denominators 3/4-3/8
1 answer:
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Lagrange multipliers:
(if 
)
(if )
(if 
)
In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force 
, so the point we found is the only extremum.
In the first octant, we assume
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
We also need to check the boundary of the region, i.e. the intersection of
Answer:
See below, please!
Step-by-step explanation:
We can set up a system of equations to model this problem. Let's consider the student's ticket as x, and y for the adult ticket.
So since the student ticket is $1.50, and adult is $4, we can set up the following equation: , since they collected $5050 total.
We can set up another equation modeling the number of people who came to the game. This would be x+y=2200.
Solve this, and we get x= 1500 and y=700. So, they sold 1500 student tickets and 700 adult tickets.
Hope this helped!