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Andrew [12]
3 years ago
8

M=(N-2)/N solve for N

Mathematics
1 answer:
Tpy6a [65]3 years ago
4 0

M = (N-2)/N

M = N² - 2N

N² - 2N - M = 0

To find N we need to use quadratic formula.

For our equation x = N, a=1, b= -2, c= -M

x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}
\\ \\N=\frac{-(-2)+/-\sqrt{(-2)^{2} -4*1*(-M)} }{2*1}
\\ \\ N=\frac{2+/-\sqrt{4+4M} }{2} \\ \\ N=\frac{-2+/-2\sqrt{1+M} }{2} = -1+/-\sqrt{1+M} \\ \\ N = -1 +\sqrt{1+M} \ or\ N=-1-\sqrt{1+M}


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