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In-s [12.5K]
4 years ago
8

Andy's total college tuition and fees for a term in which he enrolls in 15 credit hours is $9064. His fees for the term are as f

ollows.
Student Fees: $1036
Housing: $3450
Meal plan: $1653
Write a linear equation and solve it to determine how much he is charged per credit hour. Enter the cost per credit hour in the box below.
Mathematics
1 answer:
Westkost [7]4 years ago
5 0

Answer: The required linear equation 15y=9064-(1036+3450+1653)

He charged $195 per credit hour.

Step-by-step explanation:

Given: Andy's total college tuition and fees for a term in which he enrolls in 15 credit hours= $9064

According to the question, the total tuition fees for 15 credit hours = 9064-(1036+3450+1653)

Let y be he charged per credit hour, then the linear equation for the given situation will be

15y=9064-(1036+3450+1653)\\\Rightarrow\ 15y=9064-6193\\\Rightarrow\ 15y=2925\\\Rightarrow\ y=\frac{2925}{15}\\\Rightarrow\ y=\$195

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Read 2 more answers
Of the entering class at a​ college, 75​% attended public high​ school, 15​% attended private high​ school, and 10​% were home s
poizon [28]

Answer:

a)- 0.7670

b)- 0.176

c)- 0.809

Step-by-step explanation:

Let us assume that,

P(A)= Attended Public School

     =0.75

P(B)= Attended Private School

     =0.15

P(C)= Attended Home School

     =0.10

P(E)= Student made the Dean's list

Then,

P(E/A)= Probability of Student made the Dean's list given that he\she attended Public School = 0.18

P(E/B)= Probability of Student made the Dean's list given that he\she attended Private School = 0.16

P(E/C)= Probability of Student made the Dean's list given that he\she is from Home School = 0.17

a)- P(E)= Probability that Student made the Dean's List

          = P(A) × P(E/A) + P(B) × P(E/B) + P(C) × P(E/C)

          = 0.75 × 0.18 + 0.15 × 0.16 + 0.10 × 0.17

          = 0.176

b)- P(A/E) =  Probability that Student came from a Public high school​,         given that Student made the​ Dean's list

              =  [ P(E/A) × P(A) ] ÷ P(E)

              = [ 0.18 × 0.75 ] ÷ 0.176

              = 0.767

c)- P(C'/E') = Probability that Student was not home schooled​, given that the Student did not make the​ Dean's list

                 = [ P(E'/C') × P(C') ] ÷ P(E')

                 = [ 0.741 × 0.90 ] ÷ 0.82         [∵P(E'/C')=P(A)×P(E'/A)+P(B)×P(E'/B)

                                                                                = 0.75 × 0.82 + 0.15 × 0.84

                                                                                = 0.741

                  = 0.809

8 0
4 years ago
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