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Leona [35]
3 years ago
15

Place

Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0

Answer:

P(A\ and\ B) = \frac{3}{7}

Step-by-step explanation:

<em>Your question is not well presented; (See Attachment for complete details)</em>

<em></em>

Required

Find P(A n B)

where

A = Event that the place is a city

B = Event that the place is in North

The first step is to get the sample space;

Let S represent the sample space;

S = \{India,\ Tokyo,\ Houston,\ Peru,\ New York,\ Tijuana,\ Canada \}

n(S) = 7

The next is to list events A and B

A = City

A = \{Tokyo,\ Houston,\ New York,\ Tijuana\}

B = North America

B = \{Houston,\ New York,\ Tijuana,\ Canada\}

The next is to list common elements in A and B

A\ n\ B = \{Houston,\ New York,\ Tijuana\}

n(A\ and\ B) = 3

The probability of A and B is calculated as follows;

P(A\ and\ B) = \frac{n(A\ and\ B)}{n(S)}

Substitute n(A\ and\ B) = 3 and n(S) = 7 in the expression above

P(A\ and\ B) = \frac{3}{7}

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Step-by-step explanation:

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(2x+3y+4z)(4x^2+9y^2+16z^2-6xy-12yz-8zx)
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Thoughtfully split the expression at hand into groups, each group having two terms :

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Group 2: 16z2-8xz
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Pull out from each group separately :

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Group 2: (x-2z) • (-8z)
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