Question

Suppose users share a 1 Mbps link. Also suppose each user

Answer 1

Answer:

The answer is below

Explanation:

A) The total bandwidth = 1 Mbps = 1000 Kbps

The requirement for each user = 100 Kbps

Total number of users = Total bandwidth /  requirement for each user

Total number of users = 1000 Kbps / 100 Kbps = 10 users

B) Since each user transmits only 10 percent  of the time, probability that a given user is transmitting is:

Probability = 0.1

C) Binomial distribution formula is given by:

$P(x)= C(n,x)p^x(1-p)^{n-x}\\\\n = number\ of \ trials,x=number\ of\ success, p=probability\ of\ success \ for\ one\ trial$Hence:

Probability=$(50\ choose\ n)p^n(1-p)^{50-n}$

$P=C(50,n)p^n(1-p)^{50-n}$

D) The probability that there are 11 or more is:

$Probability=1-\Sigma\limits^{20}_0 {(50\ choose\ n)p^n(1-p)^{50-n}}$