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3 years ago

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In a laboratory, a scientist is using a cylindrical beaker whose length is 11 cm. The diameter of the beaker is 6 cm. How much a

cid can it hold? (Use 3.14 for π .)

1 answer:

sesenic [268]3 years ago

8 0

Use V = pi x r^2 x h
V = 3.14 x 3^2 x 11
V = 310.86

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Options for awnser is a,b,c,d

Aleks04 [339]

Answer:

Step-by-step explanation:

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The right answer is D

We should rotate the R point 3/4 a circle clockwise so it falls on D point.

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3 years ago

Read 2 more answers

From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin

borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

$C_{n,x} = \frac{12!}{4!(8)!} = 495$

495 combinations of 4 students can be selected.

8 0

3 years ago

Answer pleaseee not 120

hjlf

Answer:

x=82

Step-by-step explanation:

53+45=98

180-98=82

8 0

2 years ago

A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the

Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

$P(A) = 0.90*0.03 + 0.1*0.97 = 0.124$

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

$P(A \cap B) = 0.9*0.03 = 0.027$

What is the conditional probability that she does, in fact, have the disease

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177$

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0

3 years ago

on monday mrs jones spent 32 dollars on 4 books. on tuesday she spent $16 on more books.each book cost the same amount. how many

Gala2k [10]

She bought 6 books in all because if you divide the whole number of all the books in all which is $32 divide that by 4 so..

32 ÷4=8

so thats just the 4 books then she buys 16 more dollars worth that which you then multiply 4 times 8 which give you 16 so you then add the 4 books to the other 2 books spent on the next day

ANSWER: 6 BOOKS IN ALL

6 0

3 years ago