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Over [174]
3 years ago
14

Let u solve cu = 0. Show that any derivative, say w = uxt, also solves cw = 0. In cu = 0, u = u(t, x) do the change of variables

(ξ, η) specified below, to find the equation for v(ξ, η). Is it vξξ − c 2vηη = 0? (a) Translation ξ = t − T, η = x − y where y, T are fixed. (b) Dilation ξ = at, η = ax for any constant a. (c) Find the change of variables (ξ, η) = (?, ?) such that v(ξ, η) satisfies 1v = vξξ −vηη = 0

Mathematics
1 answer:
hjlf3 years ago
4 0

Answer:

See the pictures attached

Step-by-step explanation:

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A publisher reports that 30% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is
Ierofanga [76]

Answer:

Test statistic = - 2.29

Pvalue = 0.0110

Step-by-step explanation:

The hypothesis :

H0 : p = 0.3

H1 : p < 0.3

Test statistic :

z=pˆ−p/√p(1−p)/n

pˆ = 0.2

Z = (0.20 - 0.30) / √(0.30(1 - 0.30) / 110

Z = - 0.1 / √0.0019090

Z = - 0.1 / 0.0436931

Z = - 2.29

Test statistic = -2.29

The Pvalue :

P(Z < -2.29) = 0.0110

4 0
3 years ago
Need Help With Math Problem
ioda
It’s b i’ve had this before
7 0
3 years ago
Hello, no rush, but I need to know the answer for 4(x-2+y)
bixtya [17]

Answer:

It's 4x - 8 + 4y

Step-by-step explanation:

4(x-2+y)

4 (x) = 4x

4 (2) = 8

4 (y) = 4y

4x - 8 + 4y

3 0
3 years ago
The value, v, of your quarters (in cents) is a function of n, the number of quarters you have.
Snezhnost [94]
The independent variable is the one you change to get your dependent variable. in this case, the independent would be the number of quarters you have
3 0
2 years ago
All changes saved
slamgirl [31]
Your answer would be :A


Explanation: He claims to have had 9 sales “per day” for the week. When really it was only for 2 days. That being Thursday and Tuesday! The Mode number of the sales is 9; which is only higher from most of the days.


I hope this helps. Let me know if I am wrong plz. It’s 1 in the morning for me right now. Lol Have a blessed day bud.
4 0
3 years ago
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