There are $5$ girls and $5$ boys in a chess club. The club holds a round-robin tournament in which every player plays against ev
ery other player exactly once.
What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form.
1 answer:
To get the total number of games possible, we will use the combination formula.
Total number of games :

= 45
Total of 45 games in the whole tournament.
Meanwhile, if there would be boy-versus-boy, we will have

The answer is 10.
The fraction for boy-versus-boy game will be
10/45 or 2/9 when simplified.
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