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forsale [732]
3 years ago
5

There are $5$ girls and $5$ boys in a chess club. The club holds a round-robin tournament in which every player plays against ev

ery other player exactly once.
What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form.
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0
To get the total number of games possible, we will use the combination formula. 
Total number of games :  _{10}C_{2} = 45

Total of 45 games in the whole tournament.

Meanwhile, if there would be boy-versus-boy, we will have _{5}C_{2}
The answer is 10. 

The fraction for boy-versus-boy game will be 10/45 or 2/9 when simplified.
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