Recall that for , we have the convergent geometric series
Now, for , we have
Integrating both sides gives
If we let , the sum on the right side drops out and we're left with
.
It follows that
or
There are $5$ girls and $5$ boys in a chess club. The club holds a round-robin tournament in which every player plays against ev
1 answer:
To get the total number of games possible, we will use the combination formula.
Total number of games :
= 45
Total of 45 games in the whole tournament.
Meanwhile, if there would be boy-versus-boy, we will have
The answer is 10.
The fraction for boy-versus-boy game will be 10/45 or 2/9 when simplified.
Total number of games :
Total of 45 games in the whole tournament.
Meanwhile, if there would be boy-versus-boy, we will have
The answer is 10.
The fraction for boy-versus-boy game will be 10/45 or 2/9 when simplified.
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By Cramer's rule, the solution can be found as the ratio of determinants. The numerator is the matrix with the right-side constants replacing the coefficients of the variable of interest. The denominator is the matrix of coefficients.
The solution is ...
... B. (1, 4)