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LuckyWell [14K]
3 years ago
15

hurrrrrrrrrry!!!!! There are 2 Senators from each of 50 states. We wish to make a 3-Senator committee in which no two members ar

e from the same state.How many ways can we choose a Senator from a chosen state?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

You can choose one senator in 2 ways from the first of the 3 states; in 2 independent ways from the second of the 3 states; and in 2 independent ways from the third of the 3 states.

Step-by-step explanation:

So the answer to that question is 2*2*2*19600 which = 156800 way

Step-by-step explanation:

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Q10. Consider the following algorithm:
maw [93]

Answer:

  61,940

Step-by-step explanation:

For a recursive sequence of reasonable length, it is convenient to use a suitable calculator for figuring the terms of it. Since each term not only depends on previous terms, but also depends on the term number, it works well to use a spreadsheet for doing the calculations. The formula is easily entered and replicated for as many terms as may be required.

__

The result of executing the given algorithm is shown in the attachment. (We have assumed that g_1 means g[-1], and that g_2 means g[-2]. These are the starting values required to compute g[0] when k=0.

That calculation looks like ...

  g[0] = (0 -1)×g[-1] +g[-2} = (-1)(9) +5 = -4

The attachment shows the last term (for k=8) is 61,940.

8 0
2 years ago
Can someone explain how to do this
n200080 [17]
You need to divide the miles by the hours to et the Average speed.
M divided by h = s
Because to get the mph (miles per hour) you multiply the average speed to the hours.
S•h=mph
8 0
3 years ago
I nene help with this please. It a quiz
Vladimir [108]
58 if you add the two numbers then subtract the answer from 180 that’s the answer
8 0
2 years ago
Can somebody help me on 23 and 24, it’s geometry
alexdok [17]

Answer:

  23.  x = 4; DE = 44

  24.  x = 25; DS = 28

Step-by-step explanation:

23. Point S is the midpoint of DE, so ...

  DS = SE

  3x +10 = 6x -2

  12 = 3x . . . . . . . . . add 2-3x

  4 = x . . . . . . . . . . . divide by 3

Then DS has length ...

  DS = 3x +10 = 12 +10 = 22

and DE is twice that length, so ...

  DE = 44

__

24. DS is half the length of DE, so is ...

  DS = DE/2 = 56/2

  DS = 28

Then x can be found from ...

  DS = x +3

  28 -3 = x = 25 . . . . . substitute value for DS

_____

<em>Comment on problem 24</em>

Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.

8 0
3 years ago
Read 2 more answers
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
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