3 years ago

Ben simplified this expression.

Mathematics

2 answers:

harina [27]3 years ago

8 0

Answer:

Step-by-step explanation:

Alex3 years ago

4 0

Answer:

No he needed to apply the exponent to all factors in the product in the second step

Step-by-step explanation:

just did it on edg.

You might be interested in

How to do this question by proving the identity?

jeyben [28]

$\sin^3 \theta-\cos^3 \theta=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin^2 \theta+\sin \theta\cos \theta +\cos^2 \theta)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\$