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stiks02 [169]
2 years ago
6

Can someone please help me with these questions thank you

Mathematics
1 answer:
saul85 [17]2 years ago
7 0

Answer:A) What are the side lengths of the original triangle, ABC?

B) What are the side lengths of the enlarged, A’B’C?

C) Calculate the area and the perimeter of A’B’C.

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David, Ben, and Jordan shared stickers in a ratio of 8 : 9 : 10. If Ben had 36 stickers, how many stickers did Jordan have?
pantera1 [17]

Answer:

Jordan had 40 stickers.

Step-by-step explanation:

For this ratio, we have David:Ben:Jordan as 8:9:10, and so we need to make it as a more complex fraction, 8/9/10, now we need a multiplier to get us from 9 stickers of Jordan to 36, like a giant one. The common multiplier in this case is 4, and we know that the values must always stay proportional. We multiply everything by 4,and we get a final ratio of 32:36:40, and since Jordan is the last in the ratio David:Ben:Jordan, Jordan ends up with 40 stickers.

3 0
3 years ago
Andre tried to solve the equation 1/4(x + 12) = 2. What was his mistake? *
Umnica [9.8K]

Answer:

x=-4

Step-by-step explanation:

x+12=8    

x=8-12

Andre did not multiple both by four to get the exact whole number. He also, didnt subtract 12 which is not possible due to it being multiplied by 1/4.

5 0
3 years ago
Help me please I been trying to figure out how to do this problem
Marina86 [1]

sin 30 = x/4

sin 30 = 0.5

0.5 = x/4

x = 2

5 0
1 year ago
A new baby is born in France the newspaper reports the baby's mass to be 1.5×10³ kg
Ira Lisetskai [31]

The question only supplied us with the mass of the new baby which is:

1.5\cdot10^3\operatorname{kg}\Rightarrow1500\operatorname{kg}

This mass is too bizzarre & unrealistic for

4 0
1 year ago
It's from the chapter : "exponents and powers"<br>i need the workings too<br>please help​
labwork [276]

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

simplify

3^3-8/19

3^3=27

27-8/19

convert element to fraction

(27*19)/19-8/19

combine

(27*19-8)/19

505/19

Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

5 0
3 years ago
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