Using the least common multiple of 4 and 10, it is found that the smallest number of candies each order could have contained is 20 candies.
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- There are boxes of 4 candies and of 10 candies.
- Thus, the smallest possible number of equal candies on two orders in the<u> least common multiple of 4 and 10.</u>
- To find this multiple, we factor both numbers by their prime factors, thus:
4 - 10|2
2 - 5|2
1 - 5|5
1
Thus, lcm(4,10) = 2*2*5 = 20.
- The smallest possible number is 20 candies, one order with 20/4 = 5 boxes of 4 candies, and the other with 20/10 = 2 boxes of 10 candies.
A similar problem is given at brainly.com/question/24540608
Answer:
Step-by-step explanation: do 2.5*32.50 then multiply that by 3.14
Answer: 25%
Step-by-step explanation:
1/4 as a percentage is 25%
Answer: Easy, graph and solution
Step-by-step explanation: First what you want to do use the slope intercept form to find the slope and y intercept; -1/2 and y intercept (0,4). Any line can be graphed using 2 points. Select two x values, plug them into the equation to find the corresponding y values. Solution
1.) Step; x and y
Table:
0║4
8║0
- All you had to do is divide 0=-x/2 +4= . (8) For the x intercept you get 8and for y you get 4 because you divided 0=-0/2+4
