X + 9 = 11 doesn’t belong
x = 3 in all the other equations
Answer:
In mathematics and statistics, deviation is a measure of difference between the observed value of a variable and some other value, often that variable's mean.
To calculate the standard deviation of those numbers:
Work out the Mean (the simple average of the numbers)
Then for each number: subtract the Mean and square the result.
Then work out the mean of those squared differences.
Take the square root of that and we are done!
It could be 443, try simplifying to the nearest hundreaths, hope this helps!
Answer:
Step-by-step explanation:
Given the surface
G(x, y, z) =2z²
Over the hemisphere
x² + y² + z² = 36. For z≥0
Using polar coordinate
x=sin Φ cos θ,
y = sin Φ sin θ,
z = cos Φ
0 ≤ Φ ≤ π/2, 0 ≤ θ ≤ 2π
Therefore
r(Φ, θ) = sin Φ cos θ i + sin Φ sin θ j + cos Φ k
Also, dS= |rθ×rΦ|= sinΦ
dS=sinΦdΦdθ
Then we want to compute the volume integral of
∫ ∫ₛ G(x, y, z) dS
G(x, y, z) =2z²
Therefore in polar forms
G(x, y, z) =2(cos Φ)²
G(x, y, z) = 2cos²Φ
Given that dS=sinΦdΦdθ
∫ ∫ₛ G(x, y, z) dS
∫ ∫ 2cos²ΦsinΦdΦdθ at 0 ≤ Φ ≤ π/2,
0 ≤ θ ≤ 2π
∫ 2cos²ΦsinΦ •θdΦ from 0 ≤ θ ≤ 2π
2∫cos²ΦsinΦ •(2π-0)dΦ
4π∫ cos²ΦsinΦ dΦ from 0 ≤ Φ ≤ π/2
Let U = cosΦ
dU/dΦ =-sinΦ
-dU/sinΦ =dΦ
4π∫ U²sinΦ(-dU/sinΦ) 0 ≤ Φ ≤ π/2
-4π∫ U² dU
-4π U³/3, then U=cosΦ
[-4πcos³Φ / 3 ] from 0 ≤ Φ ≤ π/2
[-4π cos³(π/2)/3 - [-4π cos³(0)/3]
0+4π/3
4π/3
4π/3 unit²
