Answer:
1 Answer which is zero
Step-by-step explanation:
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There were 54 sporting events in the year 1896 hosted by the competition
What is the function to determine the number of events in 1896?
The fact that events which are 301 sporting events in 2012 are 256 more than that of the events in 1896, means that the number of events in 1896 is 256 less than that of 2012
number of events in 1896=number of events in 2012-256
number of events in 2012=310
number of events in 1896=310-256
number of events in 1896=54 events
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15 inches : 42 feet
630 ft divided by 15 in = 42 feet
(I might be wrong but I hope this helps)
Answer:
a:c=2.5:1.25
Step-by-step explanation:
2a:3b=5:6
2(2.5):3(2)=5:6
3(2):2(1.25)=6:2.5=36:15
Answer:
0.5328 = 53.28% probability that the length of hatching times is between 15 and 18 days.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 16 days and standard deviation of 2 days.
This means that 
Probability that the length of hatching times is between 15 and 18 days.
This is the p-value of Z when X = 18 subtracted by the p-value of Z when X = 15. So
X = 18



has a p-value of 0.8413
X = 15



has a p-value of 0.3085
0.8413 - 0.3085 = 0.5328
0.5328 = 53.28% probability that the length of hatching times is between 15 and 18 days.