Answer:
vertex is (4,-4) and another point is (6,0) or you could use (2,0) or many other options :)
Step-by-step explanation:
The cool thing about this question your quadratic is in factored form so your x-intercepts are easy to figure out, they are 2 and 6.
So you can plot (6,0) and (2,0).
The vertex will lie half between x=2 and x=6... so it lays at (6+2)/2=4
We just have to find the y-coordinate for when x=4.
Plug in 4 gives you (4-2)(4-6)=(2)(-2)=-4.
So the vertex is at (4,-4).
Answer:
(x+4)(6x^2 - 7)
Step-by-step explanation:
Focus on the first 2 terms first and on the second 2 terms last:
6x^3 + 24x^2 = 6x^2(x+4)
-7x-28 = -7(x+4)
We see that the factor (x+4) is common to both pairs: common to the first 2 terms and common to the last 2 terms.
Thus,
6x³ + 24x² -7x -28 = (x+4)(6x^2 - 7(x+4)
Factoring out x+4, we get (6x^2 - 7), and so 6x³ + 24x² -7x -28 in factored form is (x+4)(6x^2 - 7).
Answer: x-6
Explanation: x^2 is a DOTS, or difference of two squares. 36 is a perfect square and x^2 is a perfect square, and you are finding the difference. Therefore, you can do (x+6)(x-6). This works with any number. If there was x^2-16, it could be factored to (x+4)(x-4)