For the transformation T, write the T-1. T: (x, y) ( 2x, y + 5) T -1 (x, y) (x - 2, y - 5) (2x - 1, y + 4) (½x, y - 5)
1 answer:
<h3>Answer: Third choice</h3><h3>(½x, y - 5)</h3>
=====================================
Explanation:
The original transformation (2x, y+5) takes any x value and doubles it. So the inverse of this is to cut the x value in half. We can say x/2 since division is the opposite of multiplication. The value x/2 is the same as ½x
For the y coordinate, we add on 5 for the original transformation. Subtraction undoes addition meaning the inverse will have y-5.
Side note: the inverse notation can be written as T^(-1).
You might be interested in
The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.
Domain is the values of x in the function represented by y=f(x), for which y exists.
THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".
Now we assume the and
So here since g(x) is a polynomial function so it exists for all real x.
<em> </em>does not exists when
, so the domain of f(x) is given by all real x except 6.
Now,
So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.
But domain of both f(x) and g(x) consists of the value x=4.
Hence the statement is not TRUE universarily.
Thus the given statement about the composition of function is FALSE.
Learn more about Domain here -
#SPJ10