1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
posledela
4 years ago
11

The specific heat of copper is 0.385 j/(g · °c). if 34.2 g of copper, initially at 24.0°c, absorbs 4.689 kj, what will be the fi

nal temperature of the copper?
Chemistry
2 answers:
julia-pushkina [17]4 years ago
7 0
<span>We know the relation between heat and temperature follows the formula: Q = Ce * m * (Tf-Ti) , where Q is heat transfer, Ce is specific heat, m is mass, Tf is final temperature and Ti is initial temperature. Note that heat value is given in kj so we need to change to joules, then as heat is absorbed the final temperature will increase. 4,689 = 0.385 * 34.2 * (Tf-24) Tf = 4,689 / (0.385 * 34.2) + 24 =380.12ÂşC</span>
OLEGan [10]4 years ago
5 0

The final temperature of copper is \boxed{{\text{380}}{\text{.117}}\;{{^\circ C}}}

Further explanation:

The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

1. Intensive properties:

These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.

2. Extensive properties:

These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, enthalpy, volume, energy, size, weight, and length are some of the examples of extensive properties.

Specific heat is the amount of heat required to increase the temperature of any substance per unit mass. Specific heat capacity is also known as mass specific heat. Its SI unit is Joule (J).

The formula to calculate the heat energy of copper is as follows:

{\text{Q}}={mc\Delta T}}                                        …… (1)

Here,

Q is the amount of heat transferred.

m is the mass of copper.

c is the specific heat of copper.

{\Delta T}} is the change in temperature of copper.

Rearrange equation (1) to calculate the temperature change.

{\Delta T}}=\frac{{\text{Q}}}{{{\text{mc}}}}                                    …… (2)

The value of Q needs to be converted into J. The conversion factor for this is,

1\;{\text{kJ}}={10^3}\;{\text{J}}

So the value of Q can b calculated as follows:

\begin{gathered}{\text{Q}}=\left({{\text{4}}{\text{.689 kJ}}}\right)\left({\frac{{{\text{1}}{{\text{0}}^3}{\text{ J}}}}{{{\text{1 kJ}}}}}\right)\\=4689\;{\text{J}}\\\end{gathered}

The value of Q is 4689 J.

The value of m is 34.2 g.

The value of c is 0.385\;{\text{J/g}}\;{\text{^\circ C}}.

Substitute these values in equation (2).

\begin{gathered}{\Delta T}}=\frac{{{\text{4689 J}}}}{{\left({{\text{34}}{\text{.2 g}}}\right)\left({0.385\;{\text{J/g}}\;{^\circ C}}}\right)}}\\=356.117\;^\circ{\text{C}}\\\end{gathered}

The temperature change \left({\Delta{\text{T}}}\right) can be calculated as follows:

{\Delta T}}={{\text{T}}_{\text{f}}}-{{\text{T}}_{\text{i}}}                          …… (3)

Here,

{\Delta T}} is the change in temperature.

{{\text{T}}_{\text{f}}} is the final temperature.

{{\text{T}}_{\text{i}}} is the initial temperature.

Rearrange equation (3) to calculate the final temperature.

{{\text{T}}_{\text{f}}}={\Delta T}}+{{\text{T}}_{\text{i}}}                       …… (4)

The value of {{\text{T}}_{\text{i}}} is 24\;^\circ{\text{C}}.

The value of \Delta {\text{T}} is 356.117\;^\circ{\text{C}}

Substitute these values in equation (4).

\begin{gathered}{{\text{T}}_{\text{f}}}=356.117\;^\circ{\text{C}}+24\;^\circ{\text{C}}\\=380.117\;^\circ{\text{C}}\\\end{gathered}

So the final temperature of copper is {380}}{\mathbf{.117}}\;{\mathbf{^\circ C}}.

Learn more:

1. What is the equilibrium constant of pure water at  ? brainly.com/question/3467841

2. Calculate the wavelength of the electron: brainly.com/question/6352445

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: intensive, extensive, enthalpy, specific heat of copper, copper, m, Q, initial temperature, final temperature, change in temperature, mass of copper, amount of heat transferred and 380.117 degree celsius.

You might be interested in
Color change is a good way to detect a chemical reaction. True or False?
Airida [17]
This is commonly true, but not always.
3 0
4 years ago
Read 2 more answers
What sentence describes energy
kaheart [24]

Answer:

It measures the capacity to do work.

Explanation:

8 0
3 years ago
Read 2 more answers
Tetrahydrocannabinol (thc) is composed of 80.24% carbon, 9.62% hydrogen and 10.14% oxygen by mass. what is the empirical formula
Alika [10]
80.24% carbon, 9.62% hydrogen and 10.14% oxygen

1) Base: 100 g

C: 80.24 g
H: 9.62 g
O: 10.14 g
      ----------
      100.00 g

2) Conversion to moles

C: 80.24 g / 12.00 g /mol = 6.687 mol
H: 9.62 g / 1.00 g/mol = 9.62 mol
O: 10.14 g / 16.00 g/mol = 0.63375 mol

3) Ratio

C:6.687 / 0.63375 = 10.55
H: 9.62 / 0.63375 = 15.18
O: 0.63375 / 0.63375 = 1

Given that the tenth of C is 0.5 you need to multiply all the numbers by 2 =>

C: 10.55 * 2 = 21.1--> 21
H: 15.18 * 2 = 30.36 -> 30
O: 1 * 2 = 2

=> C21 H30 O2

Answer: C21 H30 O2
7 0
3 years ago
The chemical properties of ca are most similar to the chemical properties of ?
EastWind [94]
<span>some elements would be Beryllium, Barium, Magnesium, and Strontium</span>
6 0
3 years ago
Name two elements that have the same properties as calcium (Ca).
Norma-Jean [14]
Members of the same group on the periodic table would have the same properties. beryllium<span>, </span>magnesium<span>, </span>strontium<span>, </span>barium<span>, and </span><span>radium has all the same properties because they are in the same group. </span>
3 0
4 years ago
Read 2 more answers
Other questions:
  • A student has a 2.123 g sample of a hydrated salt. she heats it to drive off all the water. after heating to constant mass, the
    6·1 answer
  • How might you estimate the minimum temperature
    8·1 answer
  • Which sample is most likely to undergo the smallest change in temperature upon the absorption of 100 kj of heat?
    9·1 answer
  • What is the mass percent of nitrogen in ammonium carbonate, (NH4)2CO3?
    7·1 answer
  • Epsom salt is commonly purchased in the pharmacy for a variety of uses, anti-inflammatory, laxative, and cosmetic. epsom salt is
    8·2 answers
  • Chemistry
    12·1 answer
  • 1. Why is the majority of freshwater not available for use?
    8·1 answer
  • When a sponge gets wet, does it become more massive
    11·2 answers
  • According to the particle theory of matter, what is the difference between ice and water?
    9·1 answer
  • A molecule is
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!