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2 years ago

How has America changed over the years

1 answer:

3 0

Working no longer means heading into an office.
Exercise isn't just for fitness fanatics anymore.
Virtually nobody has a home phone.
We interact completely differently.
Dating means little more than swiping right.
TV has become a bottomless resource.
Anyone can become a celebrity.

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There are 23 countries in North America, 12 countries in South America, 47 countries in Europe, 44 countries in Asia, 54 countri

natta225 [31]

The probability for each event follows below:

P(A)= 0.23

P(E)= 0.24

P(F)= 0.28

P(N)= 0.12

P(O)= 0.07

P(S)= 0.06

<h3>Probability</h3>

Probability can be defined as the possibility that an event will occur. For an event, the probability can be found from the ratio between the number of favorable outcomes for the event and the total number of outcomes. Values of probability vary between 0 and 1.

A probability for an event is represented by P(A), P(B), etc. And exactly this that question asks for you.

1. Arrange the text of the question

North America=23 countries

South America= 12 countries

Europe= 47 countries

Asia= 44 countries

Africa =54 countries

Oceania= 14 countries

2. Find the total of countries

$N_{total}=23+12+47+44+54+14=194$

3. Find P(A)

A= the event that a country is in Asia= 44 countries. Therefore,

$P(A)=\frac{numberofcountries of Asia}{Total number of countries } \\ \\ P(A)=\frac{44}{194} =0.23\\ \\ P(A)=0.23$

4. Find P(E)

E= the event that a country is in Europe= 47 countries. Therefore,

$P(E)=\frac{numberofcountries of Europe}{Total number of countries } \\ \\ P(E)=\frac{47}{194} =0.24\\ \\ P(E)=0.24$

5. Find P(F)

F= the event that a country is in Africa= 54 countries. Therefore,

$P(F)=\frac{numberofcountries of Africa}{Total number of countries } \\ \\ P(F)=\frac{54}{194} =0.28\\ \\ P(F)=0.28$

6. Find P(N)

N= the event that a country is in North America= 23 countries. Therefore,

$P(N)=\frac{numberofcountries of North America}{Total number of countries } \\ \\ P(N)=\frac{23}{194} =0.12\\ \\ P(N)=0.12$

7. Find P(O)

O= the event that a country is in Oceania= 14 countries. Therefore,

$P(O)=\frac{numberofcountries of Oceania}{Total number of countries } \\ \\ P(O)=\frac{14}{194} =0.07\\ \\ P(O)=0.07$

8. Find P(S)

S= the event that a country is in South America= 12 countries. Therefore,

$P(S)=\frac{numberofcountries of South America}{Total number of countries } \\ \\ P(S)=\frac{12}{194} =0.06\\ \\ P(S)=0.06$

Learn more about probability here:

brainly.com/question/19916581

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2 years ago

What are 5 steps in resolving interpersonal conflict?

Dafna11 [192]

Answer:

Step 1: Define the source of the conflict.

Step 2: Look beyond the incident.

Step 3: Request solutions.

Step 4: Identify solutions both disputants can support.

Step 5: Agreement.

7 0

3 years ago

Define a constellation.

Pachacha [2.7K]

Answer:

1 : the configuration of stars especially at one's birth. 2 : any of 88 arbitrary configurations of stars or an area of the celestial sphere covering one of these configurations the constellation Orion. 3 : an assemblage, collection, or group of usually related persons, qualities, or things …

8 0

3 years ago

With the use/abuse of alcohol the heart is less efficient.

Gala2k [10]

Answer:

Explanation:

because it is overloading the heart with a non regular item.

6 0

2 years ago

A survey found that women's heights are normally distributed with mean

zheka24 [161]

Answer:

a. 99.30% of the woman meet the height requirement

b. If all women are eligible except the shortest 1% and the tallest 2%, then height should be between 58.32 and 68.83

Explanation:

<em>According to the survey</em>, women's heights are normally distributed with mean 63.9 and standard deviation 2.4

A branch of the military requires women's heights to be between 58 in and 80 in. We need to find the probabilities that heights fall between 58 in and 80 in in this distribution. We need to find z-scores of the values 58 in and 80 in. Z-score shows how many standard deviations far are the values from the mean. Therefore they subtracted from the mean and divided by the standard deviation:

z-score of 58 in= $z=\frac{58-63.9}{2.4}$ = -2.458