All categories

3 years ago

How do I turn two points into slope intercept form

1 answer:

6 0

You use those points and first find the sloope. so change in y over change in x

then once you find the slope. you plug in the points into y=mx+b
ex: if you figured out that m=1 (the slope)
then y= 1x +b..so then say you know that one point is 1,1
so 1=1(1)+b so then b =1////
hope this helps
(brainliest answer greatly aprreciated (:)

You might be interested in

The degree of the polynomial function f(x) is 4. The roots of the equation f(x) =0 are -2,-1,1 and 3. Which graph could be the g

In-s [12.5K]

Answer:

top right

Step-by-step explanation:

roots of an equation = x-intercepts

7 0

3 years ago

Read 2 more answers

6. A tank contains 100-gallon of pure water. At time t = 0, a solution containing 2 lb of salt per gallon flows into the tank at

SOVA2 [1]

Answer:

The answer is below

Step-by-step explanation:

Let Q represent the amount of salt in the tank at time t.

$\frac{dQ}{dt}= flow\ in - flow\ out\\ \\flow\ in=3\ gal/min*2\ lb/gal=6\ lb/min\\\\net\ gain\ in\ tank\ volume=3-4=-1, henceflow\ out= \frac{4Q}{100-t} \\\\\frac{dQ}{dt}= 6-\frac{4Q}{100-t} \\\\\frac{dQ}{dt}+ \frac{4Q}{100-t}=6\\\\The \ integrating\ factor\ is:\\\\IF=e^{\int\limits {\frac{4}{100-t} } \, dt }=e^{-4\int\limits {\frac{-1}{100-t}}=e^{-4ln(100-t)}=(100-t)^{-4}}\\\\Multiplying\ through \ by\ IF: \\\\(100-t)^{-4}\frac{dQ}{dt}+ (100-t)^{-4}\frac{4Q}{100-t}=6(100-t)^{-4}\\\\$

$Integrating:\\\\A(100-t)^{-4}=-2(100-t)^{-3}+c\\\\A=-2(100-t)+\frac{c}{(100-t)^{-4}} \\\\at, t=0,A=0\\\\0=-2(100-0)+\frac{c}{(100-0)^{-4}}\\\\c=0.02\\\\A=-2(100-t)+\frac{0.02}{(100-t)^{-4}}$

7 0

3 years ago

Mariela earned the following test scores in math: 95, 90, 100, 85, 80 Mr. Adams accidentally entered Mariela’s next test score a

Vesnalui [34]

Answer:

Before the error, the mean and the median were both 90.

The error added an outlier to the data set.

After the error, the mean was 75 and the median was 87.5

The mean was impacted by the error more than the median

Step-by-step explanation:

First is to put the data in order from smallest to largest

80,85,90,95,100

The mean is add up the data and divide by the number of points. The median is the middle of the data

Mean = (80+85+90+95+100)/5=450/5 = 90

Median = 90

When a 0 is added

0, 80,85,90,95,100

There is now an outlier, which is a data point far away from the others

Mean = (0+80+85+90+95+100)/6=450/6 = 75

Median = (85+90)/2 = 87.5

When the data set is even, take the two middle numbers and average them

The mean was impacted more than the median. It went from 90 to 75, where the median went from 90 to 87.5

5 0

3 years ago

Read 2 more answers

Find the value of x. Round to the nearest whole number.

IrinaVladis [17]

Use trigonometry.

sin x = opposite ÷ hypotenuse

sin x = 7/9

Take the arcsin on both sides.

arcsin(sin x) = arcsin(7/9)

x = 51.057558731

Rounding to the nearest whole number means to round to the ones place.

Answer: x = 51 degrees

5 0

3 years ago

(−5)3x7(yz)4 / (3)2x2y8z2

g100num [7]

Answer:

$\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}$

Step-by-step explanation:

Given:

The expression to simplify is given as:

$\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}$

In order to simplify this, we have to use the law of indices.

1. $(ab)^m=a^mb^m$

So, $(yz)^4=y^4z^4$

Substitute this value in the above expression. This gives,

$=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)$

Now, we use another law of indices.

2. $\frac{a^m}{a^n}=a^{m-n}$

So, $\frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2$

Substitute these values in the above expression. This gives,

$=\frac{-15}{6}\times x^5\times y^{-4}\times z^2\\\\=\frac{-5x^5y^{-4}z^2}{2}$

Finally, we further simplify it using the law $a^{-m}=\frac{1}{a^m}$

So, $y^{-4}=\frac{1}{y^4}$

Therefore, the given expression is simplified as:

$\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}$

5 0

3 years ago