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tino4ka555 [31]
2 years ago
12

Solve 2/3 (6x+30)=x+5(x+4)–2x

Mathematics
1 answer:
wlad13 [49]2 years ago
8 0
Expand the left hand side of the equation first. this is easy since two thirds of six is four and two thirds or thirty is twenty.
4x + 20 = x + 5(x+4) - 2x
expand the right hand side :
4x + 20 = x + 5x + 20 -2x

Collect up all the x terms on the right hand side: 4x + 20 = x + 5x - 2x + 20
So the total number of "x" 's on the right hand side is 1 + 5 -2 = 4
4x + 20 = 4x + 20
Hey ! look at that ! you've got the same thing on both sides of the equation ! this means that it doesn't matter what value x is, the equation works for ALL values of x . ( ANSWER)
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Reason 3: Definition of Parallelogram
Reason 4: Alternate Interior Angles Theorem
Reason 5: Reflexive Property of Congruence
Reason 6: ASA Congruence Property

------------------------------------------------------

Explanations:

Explanation for Reason 3: A parallelogram, by definition, has opposite sides that are parallel. It's built into the name more or less. Sides AB and CD are opposite one another in the parallelogram so they are parallel segments

Explanation for Reason 4: Angle ABD is congruent to angle CDB because they are alternate interior angles. They are on the inside of the "train tracks" that are formed by AB and CD. They lay on opposite sides of the transversal BD

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Step-by-step explanation:

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Grace [21]
<h3>Given :-</h3>

\\

  • x=y-1
  • x+2y=8

\\

<h3>To find:</h3>

\\

  • Value of x
  • Value of y

\\

<h3>Solution:-</h3>

Let say it is first equation:-

x=y-1. . . . (1)

and this is second equation:-

x+2y=8 . . . . (2)

\\  \\

Simplifying 1 equation:-

  • x = y - 1
  • x +1 = y
  • y = x + 1

Put this value of y in second equation.

\\

\dashrightarrow \sf \: x+2y=8

\\

\dashrightarrow \sf \: x+2(x + 1)=8

\\

\dashrightarrow \sf \: x+2x +2=8

\\  \\

\dashrightarrow \sf \: 3x +2=8

\\  \\

\dashrightarrow \sf \: 3x=8 - 2

\\  \\

\dashrightarrow \sf \: 3x=6

\\  \\

\dashrightarrow \sf \: x=6 \div 3

\\  \\

\dashrightarrow \sf \: x= \bf2

\\

to find value of y :-

y = x + 1

y = 2 + 1

y = 3

\\

verification:-

\\

1 equation:-

x = y - 1

put value of x and y

2 = 3 - 1

2 = 2

LHS = RHS

Hence verified!

\\

2 equation:-

\\

  • x+2y=8

put value of x and y

  • 2 + 2 × 3 = 8
  • 2 + 6 = 8
  • 8 = 8

LHS = RHS

Hence verified!

\\

Both equation verified!

.°. value of x and y is 2 and 3 respectively

7 0
2 years ago
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